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professor190 [17]
3 years ago
13

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam

e-day ticket is $75. For one performance, 40 advance tickets and 25 same-day tickets were sold. The total amount paid for the tickets was $2400. What was the price of each kind of ticket?
Mathematics
1 answer:
Andre45 [30]3 years ago
3 0
Al I know is that you have to use systems of equations to solve it. Sorry
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If f(x) = -3x-5 and g(x)=4x-2, find (f-g)(x)
MA_775_DIABLO [31]

f(x) -g(x) = -3x-5 -(4x-2)

distribute

-3x-5 -4x+2

combine like terms

-7x-3

Answer:

-7x-3

6 0
3 years ago
Read 2 more answers
5) Alex's house (point F) lies on the same street as her school (point H). Alex's bus stop (point G) lies between her
vlada-n [284]

Answer:

100 meters

Step-by-step explanation:

Given the following :

Alex house = F

Alex school = H

Alex bus stop = G

FG = 2x meters

GH = 1000meters

FH = 1200 meters

Hence,

FH = FG + GH

1200 = (2x + 1000) meters

1200 = 2x + 1000

1200 - 1000 = 2x

200 = 2x

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Hence, x = 100 meters

7 0
3 years ago
In a certain city of several million people, 7.7% of the adults are unemployed. If a random sample of 300 adults in this city is
Lilit [14]

Answer: 0.2643

Step-by-step explanation:

Given : The proportion of  adults are unemployed : p=0.077

The sample size = 300

By suing normal approximation to the binomial , we have

\mu=np=300\times0.077=23.1

\sigma=\sqrt{np(1-p)}=\sqrt{300\times0.077(1-0.077)}\\\\=4.61749932323\approx4.62

Now, using formula z=\dfrac{x-\mu}{\sigma}, the z-value corresponding to 26 will be :-

z=\dfrac{26-23.1}{4.62}\approx0.63

Using standard distribution table for z , we have

P-value=P(z\geq0.63)=1-P(z

=1-0.7356527=0.2643473\approx0.2643

Hence, the probability that at least 26 in the sample are unemployed  =0.2643

6 0
3 years ago
Find the missing side lengths
Mashcka [7]

Answer:

y = 9√3

x = 18

Step-by-step explanation:

taking 30 as reference angle

b = y

p = 9

h = x

so

tan30 = p/b

1/√3 = 9/b

or, b = 9√3

so

h^2 = p^2 + b^2\\x^2 = 9^2 + y^2\\or, x^2 = 81 + (9\sqrt{3} )^2\\or, x^2 = 81 + 243\\or, x ^2 = 324\\or, x =\sqrt{324} \\\\so x = 18

7 0
3 years ago
Consider the dot plot below. Of the following statements, which two characteristics of this dot plot make the median a better ch
Vilka [71]

The data are skewed and there is an outlier statement first is correct.

<h3>What is the box and whisker plot?</h3>

A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.

We have data on the box plot.

Because the dots decrease as the number line grows, the depicted dot plot is skewed right.

The graph's "tail" is pushed toward greater positive numbers. As a result, the mean is pushed towards the graph's tail and is higher than the median.

Thus, the data are skewed and there is an outlier statement first is correct.

Learn more about the box and whisker plot here:

brainly.com/question/3209282

#SPJ1

5 0
2 years ago
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