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irina [24]
3 years ago
14

Multiply the following expressions to simplify:

Mathematics
2 answers:
ivolga24 [154]3 years ago
5 0
The answer is B! Hope it helps
Ivan3 years ago
3 0
The correct answer is B hope this helped you out !
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Show all you're work!! Point's and will mark brainliest
Musya8 [376]

Answer:

d = 7.2

Step-by-step explanation:

Step 1: Write out equation

d/1.2 = 6

Step 2: Multiply both sides by 1.2

d = 7.2

4 0
3 years ago
How do I Factor -12 out of -24k + 120
Juli2301 [7.4K]

Answer:

-12(2k-10)

Step-by-step explanation:

You divide each term by -12, and then put -12 outside of the parenthesis. The parenthesis contain the new equation you just created.

4 0
3 years ago
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How to evaluate the limit
anzhelika [568]
\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}

Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
4 0
3 years ago
5. Landon bought a new car for $16,000 and it depreciates 4.5% every year. Write a function that describes
snow_tiger [21]

Answer:

<h3>The value C(t) of the car after  5  years is $12709.</h3>

Step-by-step explanation:

Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.

<h3>To find the value C(t) of the car after  5  years:</h3>

Initial value C(0)= $16,000

Depreciation rate is  r=\frac{4.5}{100}

<h3>∴ r=0.045</h3>

Period ,  t=5 years

C(t)=C(0)(1-r)^t

Substitute the values we get

C(5)=16000(1-0.045)^5

=16000(0.955)^5

=16000(0.7943)

∴ C(5)=12708.8

<h3>The value C(t) of the car after  5  years is  $ 12709</h3>
3 0
3 years ago
Which number is divisible by both 3 and 9?
poizon [28]

Answer:

OC

Step-by-step explanation:

3 0
3 years ago
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