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SashulF [63]
3 years ago
11

last night Eli read 1\4 of his book before he fell asleep. how much of the book does he have left to read?​

Mathematics
1 answer:
TiliK225 [7]3 years ago
6 0

Answer: 3/4

Step-by-step explanation:

4/4 - 1/4 = 3/4

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(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
At a school pep rally the ratio of students who wore red to those who wore yellow is 7 to 3 their are 300 students at the rally
Serhud [2]
Red to yellow.......7:3....added = 10
so 7/10 of the total students wore red and 3/10 of the total students wore yellow

and there are 300 total students...
7/10(300) = 2100/10 = 210 wore red
3/10(300) = 900/10 = 90 wore yellow

how many more wore red.....(210 - 90) = 120 more students wore red then yellow
5 0
3 years ago
How do you increase 300 by 54%?
Vanyuwa [196]
Multiply 300 by 54%= 16,200
Divide 16,200 by 100
= 162.20
Round 162.20 to the nearest whole
= 162
hope this helps.
This is the steps to finding a percent
4 0
3 years ago
What is the midpoint of the segment shown below?
deff fn [24]

The midpoint formula is basically (averaging the x coordinates, averaging the y coordinates).

Point A: (3, 7)

Point B: (2, -1)

Midpoint x: (3 + 2) / 2 = 5 / 2

Mindpoint y: (7 - 1) / 2 = 3

Therefore, the midpoint of the segment is choice C (5/2, 3)

8 0
3 years ago
Read 2 more answers
Gia bought a computer that was 20% off the regular price of $1,280. If a 9% sales tax was added to the cost of the computer, wha
garik1379 [7]
1280*.8=1024
1024*1.09=1116.16
Tax is the last thing added, savings before tax since
8 0
3 years ago
Read 2 more answers
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