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Vinil7 [7]
3 years ago
10

Como medir la altura de un arbol usando el teorema de thales

Mathematics
1 answer:
zaharov [31]3 years ago
5 0

Answer:

????

Step-by-step explanation:

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Select the statement that represents all the solutions of the inequality.
maksim [4K]

Answer:

All rational numbers less than 7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Problem 11-93 Waltner Corporation s management... Waltner Corporation's management reports that its average delivery cycle time
Marat540 [252]

Complete question is;

Waltner Corporation's management reports that its average delivery cycle time is 25 days, its average throughput time is 7.7 days, its manufacturing cycle efficiency (MCE) is 0.43, its average move time is 0.3 day, and its average queue time is 3.00 days. Required: a. What is the wait time?

b. What is the process time?

c. What is the inspection time?

Answer:

A) Wait time = 17.3 days

B) Process time = 3.311 days

C) Inspection time = 0.789 days

Step-by-step explanation:

A) we are given;

Delivery cycle time = 25 days

throughput time = 7.7 days

The formula for wait time is calculated from;

Delivery time = wait time + throughput time

So, wait time = Delivery time - throughput time

Wait time = 25 - 7.7 = 17.3 days

B) The process time is calculated from;

MCE = Process time/throughput time

So, process time = MCE x throughput time

We are given MCE = 0.43,thus, and we already know throughput time. Thus;

Process time = 0.43 x 7.7 = 3.311 days

C) The inspection time is gotten from;

throughput time = Process time + Inspection time + Move time + Queue time

Making inspection time the subject;

inspection time = throughput time - Process time - Move time - Queue time

Move time = 0.3 days

Queue time = 3 days.

Thus;

inspection time = 7.7 - 3.311 - 0.3 - 3.3 = 0.789 days

3 0
3 years ago
Nine more than four times a number is the same as one less than twice the number find the number
klio [65]
4x + 9 = 2x - 1
4x - 2x = -1 - 9
2x = -10
x = -10/2
x = -5 <===
8 0
3 years ago
Solve the following inequality using the algebraic approach:
Morgarella [4.7K]

Answer:

b. x less-than StartFraction 10 Over 3 End fraction

7 0
3 years ago
Determine the asymptotes of the function: y=x^3-5x^2+4x-25/x^2-4x+3
igomit [66]

Answer:

Vertical A @ x=3 and x=1

Horizontal A nowhere since degree on top is higher than degree on bottom

Slant A @ y=x-1  

Step-by-step explanation:

I'm going to look for vertical first:

I'm going to factor the bottom first:  (x-3)(x-1)

So we have possible vertical asymptotes at x=3 and at x=1

To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)

3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3

Let's check x=1

1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also

There is no horizontal asymptote because degree of top is bigger than degree of bottom

There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)

                       x   -1

                --------------------------------------------------

x^2-4x+3 |      x^3-5x^2+4x-25

                  - ( x^3-4x^2+3x)

                   --------------------------------

                            -x^2 +x  -25

                       -   (-x^2+4x-3)

                          ---------------------

                                   -3x-22

So the slant asymptote is to x-1

8 0
3 years ago
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