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koban [17]
2 years ago
7

-6x - 20 = -2x + 4 - 12x

Mathematics
2 answers:
hichkok12 [17]2 years ago
6 0

Answer:

Step-by-step explanation:

-6

Alchen [17]2 years ago
5 0
The correct answer is x=3
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Select the correct answer Consider functions p and q. p(x) = log₂ (x - 1) g(x) = 2^x - 1 Which statement is true about these fun
goldenfox [79]

The x-intercept of p(x) is x = 2, the x-intercept of g(x) is x = 0, then the correct option is B.

<h3>What can we say about the x-intercepts of the given functions?</h3>

For a function f(x), the x-intercept is the value of x such that:

f(x) = 0.

Here we have:

p(x) = log₂(x - 1)

Remember that:

logₙ(1)  = 0

For any base n, then the x-intercept of p(x) is x = 2, because:

p(2) = log₂(2 - 1) = log₂(1) = 0.

The other function is:

g(x) = 2ˣ - 1

Remember that any number to the power of zero is equal to 1, then:

g(0) = 2⁰ - 1 = 1 - 1 = 0

The x-intercept of p(x) is x = 2, the x-intercept of g(x) is x = 0, then the correct option is B.

If you want to learn more about x-intercepts:

brainly.com/question/3951754

#SPJ1

8 0
2 years ago
How would you find if these two triangles are congruent?
nexus9112 [7]
Compare the small marks on the lines of the triangles, if you draw them both out next to each other, are they exactly the same? If so, they’re congruent
7 0
3 years ago
EXPAND THE POLONOMIAL <br><br> (5a+1/2b)^2 HELPPP ASAP
stepan [7]

Answer:

25a^{2}+5ab+\frac{b^{2} }{4}

Step-by-step explanation:

(5a+\frac{1}{2} b)^{2}

1. First, write out the expression without the square

(5a+\frac{1}{2} b)(5a+\frac{1}{2} b)

2. Then use foil to multiply:

5a*5a+5a*\frac{1}{2}b+\frac{1}{2}b*5a+\frac{1}{2}b*\frac{1}{2}b

=25a^{2}+5ab+\frac{b^{2} }{4}

3. That is your answer.

8 0
3 years ago
What type of function best models the data in the graph?
a_sh-v [17]

Answer: 1.)Quadratic

2.) A.

Step-by-step explanation:

3 0
3 years ago
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A certain microscope is able to magnify an object up to 100,000 times its original size. In scientific notation, 100,000 is
vova2212 [387]
1.0x10 to the fifth :)
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3 years ago
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