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algol13
3 years ago
12

Calculate the vertex of the parabola using the equation Please helppp meee :((

Mathematics
1 answer:
koban [17]3 years ago
3 0

FACTOR ALL OF THE EQUATIONS INTO "y = (x-h)^2 + k," AND THE EQUATION'S VERTEX IS (h,k)

10. y = (x+2)^2 - 11 --> (-2, -11)

11. y = -(x-4)^2 + 32 --> (4, 32)

12. y = 3(x-1)^2 - 5 --> (1, -5)

13. y = -2(x+2)^2 + 5 --> (-2, 5)

14. y = 2(x+1)^2 - 1 --> (-1, -1)

15. y = -5(x-1)^2 + 8 --> (1, 8)

16. y = 3(x-3)^2 - 26 --> (3, -26)

17. y = (x+5)^2 - 32 --> (-5, -32)

18. y = -(x-3)^2 + 10 --> (3, -10)

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A)
The question tells us that
y + z = 180
And
y=3x+20
z=x

So we put them in the first formula:

y + z = 180
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Add and get x to one side:
4x + 20 = 180
4x + 20 - 20 = 180-20
4x = 160
Divide both sides by 4
x = 40

B)
Put x back in to equation to get size of each angle:

Y =3x +20
Y=3(40)+20
Y=120+20
Y=140

Z=x
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Verify: y+z=180
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2 years ago
4^(4x-1)=32 <br><br> How do I solve this problem? Do I do 4 to the fourth power first?
yKpoI14uk [10]

Answer:

\large\boxed{x=\dfrac{7}{8}}

Step-by-step explanation:

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Hello! For ease of calculations, we can identify the time it took for the weight to bounce back to the other direction, then the other, and then back to its original position by looking at the time it took for the weight to change from 0 to 25 to 0 to -25 then back to 0. This is one whole cycle of the weight.

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ANSWER: One whole cycle of the weight took 6 seconds.
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Answer:

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