The first thing you should do in this case is to write the expression correctly:
- (1/9) y + (1/3)
Now, we take out common factor (1/9) obtaining:
1/9 (-y + 3)
Let's check:
1/9 (-y + 3)
-1/9y + 3/9
-1/9y + 1/3
OK
Answer:
An expression equivalent is:
1/9 (-y + 3)
900-2*x>500
2x<900-500
2x<400
x<200
Answer:Beth can ride the bus less 200 times
We'll take out LCM of 24 seconds and 28 seconds.
that is, 168 seconds.
That means,
Car A and Car B will be side by side to each other after 2 mins 48 seconds after start.
Answer:
10) min = 5
max = 225
IRQ = 60
That's all I got
sorry
Step-by-step explanation:
<h3>
Answer: Choice A) 0.20</h3>
===================================================
Explanation:
Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.
- 65% of them are in math. So there are 0.65*1000 = 650 math students.
- 43% are in science, leading to 0.43*1000 = 430 science students.
- 13% are in both so we have 0.13*1000 = 130 students who are in both.
Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"
This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.
Of those 650 math students, 130 are also in science (since 130 are in both classes).
The probability we're after is therefore 130/650 = 0.20
