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3 years ago

What is the solution to 4x + 3 = 5 + x

Mathematics

2 answers:

dolphi86 [110]3 years ago

4 0

Answer:

0.667

Step-by-step explanation:

subtract 1 x from both sides

3x+3=5

then subtract 3 from both sides

3x=2

then divide both sides by 3 to get x alone

Answer: O.66666 repeating and round

artcher [175]3 years ago

3 0

X= 2/3 is the answer :)

You might be interested in

Y -13<br> --------- =<br> y -7<br><br>

mario62 [17]

y-13 / y-7

cross multiply

y-13 = y-7

collect like terms

y+y =-7+13

2y= 13 -7

2y = 6

divide both sides by 2

2y/ 2y = 6/2

y= 3

I hope this helped

4 0

3 years ago

The area of a rectangular piece of cardboard is represented by

Liula [17]

This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.

Area of a rectangle:

The area of rectangle of length l and width w is given by:

$A = wl$

w(2w + 3) = 9

From this, we get that:

$l = 2w + 3, A = 9$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

In this question:

$w(2w+3) = 9$

$2w^2 + 3w - 9 = 0$

Thus a quadratic equation with $a = 2, b = 3, c = -9$

Then

$\Delta = 3^2 - 4(2)(-9) = 81$

$w_{1} = \frac{-3 + \sqrt{81}}{2*2} = 1.5$

$w_{2} = \frac{-3 - \sqrt{81}}{2*2} = -3$

Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.

Another similar problem can be found at brainly.com/question/16995958

5 0

3 years ago

Consider the function f(x) = (x − 3)2(x + 2)2(x − 1). The zero has a multiplicity of 1. The zero −2 has a multiplicity of?

Gnom [1K]

The -2 has a multiplicity of 2

Since the order of (x+2) is squared, i.e. power is 2

8 0

3 years ago

Read 2 more answers

Help ASAP!

Tema [17]

Answer:

Step-by-step explanation:

$\boxed{area \: of \: sector = \frac{1}{2} {r}^{2} θ }$

Radius= diameter ÷2

r= 32 ÷2

r= 16

$\frac{1}{2} {r}^{2} θ = \frac{512\pi}{3}$

Substitute r= 16,

$\frac{1}{2} ( {16}^{2} )(θ) = \frac{512\pi}{3}$

$128 \: θ = \frac{512\pi}{3} \\ θ = \frac{512\pi}{3} \div 128 \\ θ = \frac{512\pi}{384}$

Divide the denominator and numerator by 128:

$θ = \frac{4\pi}{3}$

Thus, the answer is B.

3 0

3 years ago

In ⊙P, QR≅ST. Which statement must be true? Select all that apply.

den301095 [7]

The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π

<h3>The circle with center P</h3>

Given that the circle has a center P

It means that lengths PQ, PR, PS and PT

From the question, we understand that QR = ST.

This implies that triangles QRP and STP are congruent.

i.e. △QRP ≅ △STP is true

<h3>The length of the minor arc</h3>

The given parameters are:

Angle, Ф = 99

Radius, r = 1

The length of the arc is:

L = Ф/360 * 2πr

So, we have:

L = 99/360 * 2π * 1

Evaluate

L = 198/360π

Divide

L = 11/20π

Hence, the length of the minor arc is 11/20π