<span>A- 4 quarts over 8.7 gallon
B- 1 gallon over 4 quarts
C- 8.7 gallons over 4 quarts
D- 4 quarts over 1 gallon</span><span>Update: </span><span>Remember that 1 gallon = 4 quarts
</span>
Distance formula = sqrt[(x1 - x2)^2 + (y2-y1)^2]
D = sqrt[(1 + 2)^2 + (5 - 1)^2]
D = sqrt[3^2 + 4^2]
D = sqrt(9 + 16)
D = sqrt(25)
D = 5
What is the interquartile range for the data set 4,7,7,3,5,2,6,7,9 the answers are 3.5, 5.6, 7,9
polet [3.4K]
5.6 is the answer for your question
1) We can determine by the table of values whether a function is a quadratic one by considering this example:
x | y 1st difference 2nd difference
0 0 3 -0 = 3 7-3 = 4
1 3 10 -3 = 7 11 -7 = 4
2 10 21 -10 =11 15 -11 = 4
3 21 36-21 = 15 19-5 = 4
4 36 55-36= 19
5 55
2) Let's subtract the values of y this way:
3 -0 = 3
10 -3 = 7
21 -10 = 11
36 -21 = 15
55 -36 = 19
Now let's subtract the differences we've just found:
7 -3 = 4
11-7 = 4
15-11 = 4
19-15 = 4
So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.
3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2
I think 1/3 correct me someone if i'm wrong if i am srry
