Answer:
-8>x>6
Step-by-step explanation:
I 5x+5I +22> 57subtract 22 on both sides
I5x+5I >35
SPLIT
5x+5>35 5x+5< -35 ( flip sign and 35 negative)
5x>30 5x< -40
x>6 x< -8
Draw a number line Write zero in the middle
From zero count to the left until- 8 make an open circle because- 8 is not included From -8 draw an arrow to the left (because x is less than -8)
From zero count to the right until 6 Make an open circle bc 6 is not included. From 6 draw an arrow to the right (because x is more than 6)
PART 2 is not already solved?
If you need to solve fot t
Divide both parts by pr
t= (l/ pr)
Step-by-step explanation:
Hello,
First, there are 8 possible outcomes for the game spinner.
Second, the spinner is on 5, meaning that the outcome is 5.
Try to work with this, and if you need more help, I’ll answer back if I can.
Answer:
1 / x^8
Step-by-step explanation:
We know that a^b / a^c = a^ (b-c)
x^7 / x^ 15 = x^ (7-15) = x^-8
We also that that a^-b = 1/ a^b
x^-8 = 1 / x^8
Explanation:
5(y+3)-11=-y-6 Given
5(y+3)=-y+5 . . . . addition property of equality (11 is added)
5y+15=y+5 . . . . . distributive property (5 is distributed)
5y=-y-10 . . . . . . . addition property of equality (-15 is added)
6y=-10 . . . . . . . . . addition property of equality (y is added)
y=-5/3 Division Property of Equality/Reduce
Answer:
The value of the proposition is FALSE
Step-by-step explanation:
~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ ~X) v (B ⊃ X)]
Let's start with the smallest part: ~X. The symbol ~ is negation when X is true with the negation is false and vice-versa. In this case, ~X is true (T)
~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ T) v (B ⊃ X)]
Now the parts inside parenthesis: (A ⊃ Y),(X ⊃ B),(A ≡ T) and (B ⊃ X). The symbol ⊃ is the conditional and A ⊃ Y is false when Y is false and A is true, in any other case is true. The symbol ≡ is the biconditional and A ≡ Y is true when both A and Y are true or when both are false.
(A ⊃ Y) is False (F)
(X ⊃ B) is True (T)
(A ≡ T) is True (T)
(B ⊃ X) is False (F)
~[(F) v ~(T)] ⋅ [~(T) v (F)]
The two negations inside the brackets must be taken into account:
~[(F) v F] ⋅ [F v (F)]
The symbol left inside the brackets v is the disjunction, and A v Y is false only with both are false. F v (F) is False.
~[F] ⋅ [F]
Again considerating the negation:
T⋅ [F]
Finally, the symbol ⋅ is the conjunction, and A v Y is true only with both are true.
T⋅ [F] is False.
