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krek1111 [17]
3 years ago
5

Sulfur and nitrogen oxide release into the atmosphere is most responsible for ozone depletion acid precipitation global warming

eutrophication
Physics
1 answer:
3241004551 [841]3 years ago
6 0
The answer is acid precipitation 

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Container A and container B hold samples of the same ideal gas. The volume and the pressure of container A is equal to the volum
SVETLANKA909090 [29]

Answer:

A. TA = TB/2.

Explanation:

Since container A has half as many molecules of the ideal gas in it as container B. Therefore, container A will have half the volume of gas as in container B:

V_A = \frac{1}{2}V_B

Now, from Charle's Law:

\frac{V_A}{T_A}=\frac{V_B}{T_B}\\\\\frac{1}{2}\frac{V_B}{T_A}=\frac{V_B}{T_B}\\\\T_A = \frac{T_B}{2}

Hence, the correct option is:

<u>A. TA = TB/2.</u>

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2 years ago
Explain the law of conservation of mass and how it applies to balancing chemical equations
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The law of conservation of mass<span> states that </span>mass<span> in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the </span>law of conservation of mass<span>, the </span>mass<span> of the products in a chemical reaction must equal the </span>mass<span> of the reactants.
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Every chemical equation<span> adheres to the </span>law of conservation of mass<span>, which states that </span>matter<span> cannot be created or destroyed. Therefore, there must be the same number of atoms of each element on each side of a chemical </span>equation.
5 0
3 years ago
4. In which of the following circuits will the bulb glow?
Zanzabum

Answer:

I believe is C.

Explanation:

its quite obvious:)

4 0
3 years ago
The heater element of a 120 V toaster is a 5.4 m length of nichrome wire, whose diameter is 0.48 mm. The resistivity of nichrome
Ksenya-84 [330]

Answer:

The power drawn by the toaster is closest to:

(A) 370 W

Explanation:

First we calculate the resistance of the nichrome wire (R).

R=\frac{pL}{A} =\frac{pL}{\pi r^{2} } \\

Where radious (r), resistance coefficient (p), and Length (L)

r=\frac{0.48}{2} 10^{-3} m\\\\L=5.4 m\\p=1.3*10^{-3}\varOmega  \\\\\\Replacing:\\\\R=\frac{1.3(10)^{-6} *5.4}{\pi* 0.24^{2} (10)^{-6}} =38.7940

After replace the value in the ohm law power formula to obtain the power consumed:

P=\frac{V^2}{R} =\frac{120^2}{38.7940} =371.191 Watts

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3 years ago
Which of the following is a result of gravitational forces in the Solar System?
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