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Aliun [14]
3 years ago
15

A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0 degrees. What is

the value of work being done to the object?
A) 0 joules
B) 9.6 x10^2 joules
C) 1.2 x10^3 joules
D) -9.6 x10^2 joules
E) 1.2 x10^3 joules
Physics
2 answers:
zvonat [6]3 years ago
5 0
Work done is when a force is exerted to cause a displacement in a certain object. 
the equation for work done ;
work done = force applied * displacement of the object 
when the force applied is not in the same direction as that of the displacement of the object then the effect of the force is not its whole value. The force is then applied at an angle to that of the displacement of the object, then the resultant force is the force exerted* cos of the angle between force and displacement, in this instance the angle is 40 °.
the new equation is then;
work done = force cos 40° * displacement
after substitution,
work = 25 N * 0.76 * 50 m
         = 957.55 J
round it off
         = 9.6 *10² J
the correct answer is B
Len [333]3 years ago
3 0

Answer:

(x^10)(x^2) Add the exponents 10+2=12 So... (x^12)

Explanation:

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Explain why the angle is important when lauching projectiles
yaroslaw [1]

Answer:

to have an accurate measure

Explanation:

6 0
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Austin buys a new moped he travel 3 km south and then 4 km east and then 3km north how far does he need to go to get back to whe
Ira Lisetskai [31]
The first thing to do is to define the origin of the coordinate system as the point at which the moped journey begins.
 Then, you must write the position vector:
 r = -3j + 4i + 3j
 Rewriting
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 To go back to where you started, you must go
 d = -4i
 That is to say, must travel a distance of 4Km to the west.
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4 0
3 years ago
While playing football, Chris runs 4.5 m at 20⁰ south of west. If an opponent was trying to tackle him how far west and south wo
rewona [7]

Answer:

South = 1.5m

West =4.2m

Explanation:

Kindly see attached a rough draft of the situation

Step one

Given data

From the sketch the direction of the player is along the resultant of the triangle, corresponding to the Hypotenuse

Step two:

Hence for an opponent to tackle him towards the south, he must be at

sin θ= opp/hyp

sin 20=x/4.5

x=sin 20*4.5

x=0.342*4.5

x= 1.5m

Also, for an opponent to tackle him towards the south, he must be at

cos θ= adj/hyp

cos 20=y/4.5

y=cos 20*4.5

y=0.93*4.5

y= 4.2m

5 0
3 years ago
A magnetic field is uniform over a flat, horizontal circular region with a radius of 2.00 mm, and the field varies with time. In
Shkiper50 [21]

Answer:

0.00016391 V

0.00038665 V

Explanation:

r = Radius = 2 mm

B_i = Initial magnetic field = 0

B_f = Final magnetic field = 1.5 T

t = Time taken = 115 ms

Induced emf is given by

\varepsilon=\frac{d\phi}{dt}\\\Rightarrow \varepsilon=\frac{A(B_f-B_i)}{dt}\\\Rightarrow \varepsilon=\frac{\pi 0.002^2(1.5)}{0.115}\\\Rightarrow \varepsilon=0.00016391\ V

The magnitude of the induced emf is 0.00016391 V

B_i=+1.5\ T

B_f=-0.5\ T

t = 65 ms

\varepsilon=\frac{d\phi}{dt}\\\Rightarrow \varepsilon=\frac{A(B_f-B_i)}{dt}\\\Rightarrow \varepsilon=\frac{\pi 0.002^2(-0.5-1.5)}{0.065}\\\Rightarrow \varepsilon=-0.00038665\ V

The magnitude of the induced emf is 0.00038665 V

3 0
3 years ago
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