They are feeling weightless because there is no external contact force pushing nor pulling upon their body, in each case gravity is the only force acting upon their body.
Kinetic energy is given by 1/2 MV²
k.e = 1/2 mv²
1.9 × 10^3 = 1/2m(v/2)²
1.9 ×10^3 = 1/8 mv²
1.9 × 10^3 = 1/4(1/2mv²)
= (1.9 × 10^3)/ 4
= 4.75 × 10^2 joules
The new kinetic energy will therefore be 4.7 × 10^2 joules.
Explanation:
Given that,
Object distance, u = -50 cm
Radius of curvature of the convex mirror, R = 40 cm
Focal length of the convex mirror,
We need to find the magnification of the mirror. Firstly, it is required to find the image distance using formula as:
v = 14.28 cm
Magnification of the mirror,
m = 0.28
So, the magnification of the mirror is 0.28.Hence, this is the required solution.
The energy stored in the capacitor at given capacitance and voltage is determined as 396.5 J.
<h3>Energy stored in the capacitor</h3>
The energy stored in the capacitor is calculated as follows;
E = ¹/₂CV²
where;
V is the voltage
E = ¹/₂ x 13 x 10⁻⁶ x (7.81 x 10³)²
- C is the capacitance
- V is the voltage
E = ¹/₂ x 13 x 10⁻⁶ x (7.81 x 10³)²
E = 396.5 J
Thus, the energy stored in the capacitor at given capacitance and voltage is determined as 396.5 J.
The complete question is below
An electronic defibrillator used on heart attack victims works by delivering charge stored in a capacitor. If the device utilizes a 13.0 μF capacitor charged to 7.81 × 103 V, what is the energy stored in the capacitor?
Learn more about capacitor here: brainly.com/question/13578522
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