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g100num [7]
3 years ago
7

Two colorless solutions are mixed together. Bubbles form as the solution is stirred. Give TWO possible explanations for this res

ult.
Chemistry
1 answer:
sp2606 [1]3 years ago
6 0
We are asked to give two possible explanation when bubbles are formed as two colorless solutions are mixed together. Presence of bubbles means that there is a gas formed in the products side and that the one of the reactants can be an acid. 
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What happens when a solid is dissolved into a liquid?
olga_2 [115]

Answer:

The solid has broken down into pieces so small that its particles spread all throughout the new mixture.

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2 years ago
Draw a mechanism for the reaction of methanol with sodium amide. In the box to the left, draw any necessary curved arrows. Show
Greeley [361]

Answer:

See explanation

Explanation:

When sodamide reacts with methanol, the following equilibrium is set up;

CH3OH(aq) + NH2-(aq) ⇄ CH3O-(aq) + NH3(aq)

In the reaction, the sodamide acts as a base that abstracts a proton from methanol to yield the conjugate base of methanol which is the methoxide ion.

The forward reaction is favoured at equilibrium.

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3 years ago
Which method can be used to separate a mixture of ethanol and water into its
Alex_Xolod [135]

Answer:

A, Distillation

Explanation:

4 0
3 years ago
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Label the picture, please
DochEvi [55]

Answer:

(in the pic above)

Explanation:

P= product

R= reactant

S= subscript

C= coefficient

Y= yields

4 0
3 years ago
Read 2 more answers
2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4
agasfer [191]

Answer:

d=4.24x10^{-4}\frac{lb}{in^3}

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

d=\frac{m}{V}

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

m=552.4g-464.7g=87.7g

So that we are now able to calculate the density in g/mL first:

d=\frac{87.7g}{27.8mL}=3.15g/mL

Now, we proceed to the conversion to lb/in³ by using the following setup:

d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}

Regards!

6 0
3 years ago
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