The problem ask on which of the following reactions and subsequent values and the value is given on you question. Base on your data and also to my formulation, solution and further simplification about the problem and the given values, i came up with an answer of <span>∆Hrxn = 5∆Hf(O2(g)) + 2∆Hf(C2H2(g)) - 2∆Hf(H2O(g)) - 4∆Hf(CO2(g)).</span>
Answer:
1st chemical equation → Chemical change
2nd chemical equation → Physical change
3rd chemical equation → Physical change
4th chemical equation → Chemical change
Explanation:
Chemical change has to the do with the creation of an entirely new product or substance. When two reactants react and form entirely new product(s), we say that a chemical change has occurred.
While a physical change does not create an entirely new substance or product; it can only change to a new form or state.
From the given equations, we discover that in the first equation, propane reacted with oxygen to give carbon (II) oxide and water (entirely new products) while in the second chemical equation, ethanol is a liquid (at room temperature) but later changes its state to gas (physical change).
The above answer is correct.
Amount or merchandise- please give me brainliest please
Answer:
18.
Explanation:
1) according to the reaction (M(Fe)=56; M(O₂)=32; V₀=22.4):
4Fe+3O₂⇒2Fe₂O₃; - ν(O₂)=0.75*ν(Fe);
2) ν(Fe)=m(Fe)/M(Fe)=60/56≈1.071 [mol];
3) ν(O₂)=0.75*1.071=0.804 [mol];
4) V(O₂)=V₀*ν(O₂); ⇒ V(O₂)=22.4*0.804=18 [lit].
We are given
<span>Ox: Sn(s) → Sn2+ (aq, 1.85 M) + 2e−
Red: ClO2 (g, 0.150 atm ) + e− → ClO−2 (aq, 2.00 M)
We are to compute the cell potential at 25 </span>°C
We simply have to look for the standard potentials for each of the reactions and subtract the redox standard potential from the oxidation standard potential.
From literature and after doing the operation, the answer is
Ecell = 2.2 V