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AURORKA [14]
3 years ago
14

Which pairing below does not correctly match the scientist with the contribution to the understanding of the atom? A. Proust and

the realization that the elements of compounds are found in certain proportions by mass B. Rutherford and the understanding that the atom has a small, dense nucleus with a positive charge C. Thomson and the law of definite proportions D. Dalton and the initial proposal of the atomic theory of matter
Chemistry
2 answers:
Lyrx [107]3 years ago
5 0
The answer would be C. In fact, letter A already defines the Law of Definite Proportions. On the other hand, J.J. Thomson was responsible for the discovery of electrons through cathode ray tube experiments. The rest of the choices are true.
myrzilka [38]3 years ago
3 0

Answer is: C. Thomson and the law of definite proportions.

1) J. J. Thomson discovered the electron in 1897.  

His "plum pudding" model (1904) suggested: the electrons are embedded in the positive charge.  

2) Rutherford demonstrate that J.J Thompson's Plum Pudding model was not accurate.

Rutherford theorized that atoms have their charge concentrated in a very small nucleus.

3) Proust's law or law of constant composition said that a given chemical compound always contains its component elements in fixed ratio and does not depend on method of preparation.

4) Dalton's atomic theory:

a) All matter consists of indivisible particles called atoms.  

b) Atoms of the same element are similar in shape and mass, but differ from the atoms of other elements.  

c) Atoms cannot be created or destroyed.  

d) The ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers.  

e) Atoms of same element can combine in more than one ratio to form two or more compounds.  

f) The atom is the smallest unit of matter that can take part in a chemical reaction.

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Which compound is a polar molecule and has a linear geometry
kirill115 [55]

Answer:

Linear molecule is a molecule in which atoms are deployed in a straight line (under 180° angle). Molecules with an linear electron pair geometries have sp hybridization at the central atom. An example of linear electron pair and molecular geometry are carbon dioxide (O=C=O) and beryllium hydride BeH2.

Explanation:

6 0
3 years ago
If the mass of the object below is 28g, what is the density of the object below. Units are in cm below. Please round your answer
Murljashka [212]

Answer:

d = 0.93 g/cm³

Explanation:

Given data:

Mass of object = 28 g

Volume of object = 3cm×2cm×5cm

density of object = ?

Solution:

Volume of object = 3cm × 2cm ×5cm

Volume of object = 30 cm³

Density of object:

d = m/v

by putting values,

d = 28 g/ 30 cm³

d = 0.93 g/cm³

3 0
3 years ago
URGENT:
Ad libitum [116K]

Answer:

The elements that are commonly positive ions are metals. But there are a few gases that can become positively charged by losing electrons.

8 0
3 years ago
Ms. Pitt set up a classroom demonstration to show what happens when a sample of zinc metal is add a.ed to a flask containing hyd
Nikolay [14]

Answer:

volume of HCl remains the same

7 0
2 years ago
Read 2 more answers
Using de Broglie's equation, λ = h/mv which would have a larger wavelength, a slow-moving proton or a fast-moving golf ball? Exp
tatuchka [14]

Answer: Proton will have larger wavelength

Explanation:

\lambda =\frac{h}{mv}  (de-Broglie's equation)

\lambda =\text{wavelenght of the particle}

h= Planck constant

m= mass of the particle

v= velocity of the particle

As we can see from the de-Broglie's equation , that wavelength is inversely proportional to the product of mass into velocity of the object.

The wavelength of proton will be higher than that fast moving golf ball because mass of proton (1.67 \times 10^{-24}g) is very small than that of the golf ball (45.93 g). Proton is moving  at slow velocity and the golf ball is moving with fast velocity by which value of product of mass into velocity of proton will be lower than the value of product of mass into velocity of the golf ball which will result in larger value of wavelength of the proton.

6 0
3 years ago
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