The intensity of the magnetic force F experienced by a charge q moving with speed v in a magnetic field of intensity B is equal to
where
is the angle between the directions of v and B.
1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is
. In this case, v and B are perpendicular, so
, therefore we have:
2) In this second case, the angle between v and B is
. The charge is now
, and the magnetic field is the one we found in the previous part, B=2.8 T, so we can find the intensity of the force experienced by this second charge:
The equation Q=CV (Charge = product of Capacitance and potential difference) tells us that the maximum charge that can be stored on a capacitor is equal to the product of it's capacitance and the potential difference across it. In this case the potential difference across the capacitor will be 12.0V (assuming circuit resistance is negligable) and it has a capacitance of 18.0μf or 18.0x10^-6f, therefore charge equals (18.0x10^-6)x12=2.16x10^-4C (Coulombs).
Answer:
Explanation:
When we shoot the dart upwards the time taken by the dart to go straight up and again come back is given as
here we can say
put t = 4.6 s then we have
Now in order to find the maximum range we can say
so in order to have maximum range we can say
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In the case of straight line, when the object is not repeating it's path then distance and displacement would be same.
