Answer:
Part 1)
Part 2)
Part 3)
Part 4)
Since torque on right side is more so here it will turn and slip over it
Explanation:
As we know that the block A is placed at distance
d = 50 cm from the hinge at 70 cm mark
So torque due to weight of A is given as
the block B is placed at distance
d = 30 cm from the hinge at 70 cm mark
So torque due to weight of B is given as
Now torque due to weight of the scale is given as
now torque on left side of scale is given as
Torque on right Side is given as
Since torque on right side is more so here it will turn and slip over it
Divide the change in speed by the time for the change.
Answer:
La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.
Explanation:
Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:
(1)
En donde:
F: es la fuerza magnética = 100 nN
q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C
v: es la velocidad del haz de electrones =?
B: es el campo magnético = 3500007 T
θ: es el ángulo entre el vector velocidad y el campo magnético = 90°
Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:
Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.
Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.
Espero que te sea de utilidad!
Answer:
Less than Mercury's
Explanation:
According to third Kepler's law, the square of the planet's orbital period is proportional to the cube of the average orbital radius of the planet's orbit. The constant of proportionality depends only on the mass of the star, recall that 51 Peg has the same mass as the Sun. Since the orbital period of this planet is less than Mercury's, its average orbital radius is less than Mercury's.
