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Naddik [55]
2 years ago
6

A 3-kg object is attached to a spring and moving in simple harmonic motion. Its angular frequency is 20 rads/sec. When the mass-

spring system is 0.10 m from its equilibrium position it has a velocity of v=3 m/s. What is the potential energy when the mass reaches amplitude? A. 0 J
B. 6 J
C. 13.5 J
D. 8 J
E. 19.5 J
Physics
1 answer:
Trava [24]2 years ago
7 0

Answer:19.5 J

Explanation:

Given

mass of block=3 kg

angular frequency=20 rad/sec

spring constant k=\omega _n^2m=1200 N/m

we know total energy remain conserved

E_T at x=0.1 m

E_T=E_P+E_K

Where E_K=kinetic energy

E_P=potential Energy

E_P=\frac{1}{2}kx^2

E_P=600\times 0.01=6 J

E_K=\frac{1}{2}mv^2

E_K=\frac{1}{2}\times 3\times 3^2=13.5 J

E_T=13.5+6=19.5 J

When mass reaches amplitude its velocity becomes zero

there is only potential energy which is equal to Total energy

E_T=E_P=19.5 J

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