F(x) = 2^x; h(x) = x^3 + x + 8
Table
x f(x) = 2^x h(x) = x^3 + x + 8
0 2^0 = 1 0 + 0 + 8 = 8
1 2^1 = 2 1^3 + 1 + 8 = 10
2 2^2 = 4 2^3 + 2 + 8 = 8 + 2 + 8 = 18
3 2^3 = 8 3^3 + 3 + 8 = 27 + 3 + 8 = 38
4 2^2 = 16 4^3 + 4 + 8 = 76
10 2^10 = 1024 10^3 +10 + 8 = 1018
9 2^9 = 512 9^3 + 9 + 8 = 729 + 9 + 8 = 746
Answer: an approximate value of 10
The value of constant c for which the function k(x) is continuous is zero.
<h3>What is the limit of a function?</h3>
The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.
To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:


Provided that:

Using l'Hospital's rule:

Therefore:

Hence; c = 0
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2/15+3/15=5/15 5 can go into both 5/5=1 and 15/5=3 which means
=1/3 is the answer
Answer:
5x+3
Step-by-step explanation:

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