Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
We will be using simultaneous equations to solve this problem.
First we will establish the equations which we will be using as displayed below:
Equation No. 1 -
A + B = 90°
Equation No. 1 -
A = 2B + 12
To begin with, let's make ( A ) the subject in the first equation as displayed below:
Equation No. 1 -
A + B = 90
A = 90 - B
Next we will substitute the value of ( A ) from the first equation into the second equation and solve for ( B ) as displayed below:
Equation No. 2 -
A = 2B + 12
( 90 - B ) = 2B + 12
- B - 2B = 12 - 90
- 3B = - 78
B = - 78 / - 3
B = 26°
Then we will substitute the value of ( B ) from the second equation into the first equation to solve for ( A ) as displayed below:
A = 90 - B
A = 90 - ( 26 )
A = 64°
ANSWER:
Therefore, the answer is:
A = 64°
B = 26°
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Step-by-step explanation:
Assuming figure to be trapezoid,
Perimeter=6+4+7+4yd
=21 yd
Area of trapezoid=((6+7)/2) x ((4)^2-(0.5)^2)
=(13/2)x(16-0.25)
=6.5 x 15.75
=102.375 Sq yards
Answer:
A) 5.12mm³
Step-by-step explanation:
Step 1
Find the volume of the bigger pyramid
This is a triangular based pyramid.
The formula to use is given as Volume of Pyramid =
1/3 × Area of the triangle × Height
Area of the triangle = 1/2 × 3 mm × 4mm = 6mm²
Volume of the large pyramid = 1/3 × 6mm² × 5mm
= 10mm³
We are given the length of the small pyramid as 4mm
We would be using was is known as scale factor to find the volume of the small pyramid
The scale factor k = (Height of the small pyramid)³/ (Height of the Large pyramid)³
k = 4³/5³
k = Volume of small pyramid/ Volume of large pyramid
Volume of small pyramid = X
Volume of large pyramid = 10mm³
Hence,
4³/5³ = X/10
Cross Multiply
= 4³ × 10 = 5³ × X
X = (4³ × 10)/ 5³
X = 5.12mm³
Answer:
The answer is a dilation with a scale factor less than 1 and then a reflection.
Step-by-step explanation:
