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4 years ago

How to solve word problems

2 answers:

kondor19780726 [428]4 years ago

8 0

First: Read the problem entirely.
Second: List information and variables you identify. add units of measure to tje variables.
Third: Define what the answer you are solving for is as well as the units of measurement applied.
Fourth: Work a neatly
Fifth: Look for the key words that let you know what exactly you are doing(-,+,/,*)

Lapatulllka [165]4 years ago

6 0

Read the problem entirely.
Get a feel for the whole problem.
List information and the variables you identify.
Attach units of measure to the variables (gallons, miles, inches, etc.)
Define what answer you need, as well as its units of measure.
Work in an organized manner. ...Look for the "key" words (above)

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Triangle BAC was rotated 90° clockwise and dilated at a scale factor of 2 from the origin to create triangle XYZ. Based on these

ANEK [815]

Answer:

The correct option is;

∠A ≅ ∠X

Step-by-step explanation:

The given coordinates of the points of triangle ACB are;

A(-4, 4), C(-1, 3), B(-4, 0)

The given coordinates of the points of triangle XYZ are;

X(0, 8), Y(8, 8), Z(6, 2), therefore, we have

The length. l. of segment is given by the following formula;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)

For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4

For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2

For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8

For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2

For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10

Therefore;

XY ~ AB, XZ ~ BC, ZY ~ AC

Which gives;

∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z

8 0

3 years ago

Read 2 more answers

A waterfall has a height of 1900 feet. A pebble is thrown upward from the top of the falls with an initial velocity of 12 feet p

saw5 [17]

Answer:

Step-by-step explanation:

h is the height of the pebble after a certain amount of time has gone by. Since we are told to find that time when the pebble is on the ground, we say that h = 0 since the height of something on the ground has no height at all. Then factor the quadratic.

$-16t^2+12t+1900=0$

Throw that into the quadratic formula or however you were taught to factor irrational quadratics (maybe completing the square?) to get that

t = 11.27869 sec and t = -10.52869 sec

Since we all know that time will never carry a negative value, we will disregard it and go with 11.27869 seconds. Not sure to where you are told to round.

7 0

3 years ago

Correct = Brainlest Abe digs a hole at a steady rate of 1 2/3 feet every hour. Consider ground level to be 0. What value represe

LUCKY_DIMON [66]

Answer:

$1~1/2$

Step-by-step explanation:

If he digs at a rate of $1~2/3$ feet every hour, and he needs $2~1/2$ hours, we want to find $(2~1/2)/(1~2/3)=(5/2)/(5/3)=(5*3)/(5*2)=3/2=\boxed{1~1/2}$ feet.