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Allisa [31]
2 years ago
5

Jason jogged 2/3 mile in 1/3 hour. What was his speed in miles per hour?

Mathematics
1 answer:
fenix001 [56]2 years ago
7 0

Answer:

I honestly was having the worst time trying to solve this sorry :(, for real idk if any of these are right

i got 2 answers; 1st: ≈0.5 mph

the 2nd; 2 mph

Step-by-step explanation:

Speed = \frac{Distance}{Time}

2/3 miles = 3520 feet

1/3 hours = 20 minutes

------Make a proportion-----

\frac{3520ft}{20min} = \frac{1 mi=5280 ft}{1hr = 60min}

cross multiply------

3520 * 60 = 211200

5280 * 20 = 105600

Divide \frac{211200}{105600}= 2

---(this is where i got confused cuz 2 doesn't make any sense)--

If you flip them, \frac{105600}{211200}=0.5 which makes more sense

hope i helped :(

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A patient is given a 100-milligram dosage of a drug that decays exponentially at a rate of 11% per hour. The doctor wants to kno
I am Lyosha [343]

Answer:

This is an example of exponential decay (somewhat similar to half-life).

If it decays at 11% per hour we can calculate its half-life by this formula:

half life = [ time • ln (2) ] ÷ ln (beginning amount ÷ ending amount)

where "ln" means natural log

half life =[ 1 hour * .69315] / ln (100 / 89)

half life =[.69315] / ln (1.1235955056)

half life =[.69315] / 0.11653381624

half life = 5.9481 hours


We need "lambda" "λ" (the decay constant) which equals

λ  = ln(2) / half-life = .693147 / 5.9481 = 0.1165325062


Now we need a formula for the time required:

time = ln (Nt ÷ N0) ÷ -λ where No = beginning amount (100 milligrams) Nt = ending amount (15 milligrams)

time = ln (15 ÷ 100) ÷ -0.1165325062

time = ln (.15)  /  -0.1165325062

time = -1.8971199849 / -0.1165325062


time = 16.2797492885 hours

Source: https://www.1728.org/halflif2.htm



Step-by-step explanation:


4 0
2 years ago
What does 3y-y equal?
Novosadov [1.4K]

Answer:

2y

Step-by-step explanation:

You need to subtract the coefficients to get the answer.

Let's look at the equation...

3y-y

The coefficient is 3 and 1

So, you do 3-1

You get 2

So...

3y-y=2y

4 0
3 years ago
Two cones are similar. The volume of the larger cone is 27 cm³ and the volume of the smaller cone is 8 cm³. The height of the sm
aev [14]
ANSWER

The height of the larger cone is 3cm

EXPLANATION

Since the two cones are similar we can use the scale factor to determine the height of the larger cone.

It was given that, the volume of the larger cone is 27 cm³ and the volume of the smaller cone is 8 cm³.


The scale factor for the volume is


{k}^{3}  =  \frac{27}{8}


The scale factor for the length is

k =  \sqrt[3]{ \frac{27}{8} }


k = \frac{3}{2}


To find the height of the larger cone, we multiply by

h = \frac{3}{2}  \times 2 = 3
7 0
3 years ago
Read 2 more answers
a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.
Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is a_{n} = a^{n-1} \times r

<u>Step-by-step explanation:</u>

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

<u>The first term :</u>

In geometric sequence, the first term is given as a_{1}.

⇒ a_{1} = 612

Now, the geometric sequence follows as 612, 661, ........

<u>The common ratio (r) :</u>

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

<u>To find the recursive rule :</u>

A geometric series is of the form  a,ar,ar2,ar3,ar4,ar5........

Here, first term a_{1} = a and other terms are obtained by multiplying by r.

  • Observe that each term is r times the previous term.
  • Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form a_{n} = a^{n-1} \times r

This is called recursive formula for geometric sequence.

We know that r = 1.08 and a_{1} = 612.

To find the second term a_{2}, use the recursive rule a_{n} = a^{n-1} \times r

⇒ a_{2} = a^{2-1}\times r

⇒ a_{2} = a^{1}\times r

⇒ a_{2} = 612\times 1.08

⇒ a_{2} = 661

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3 years ago
Exact length of line segment xy
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length=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
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