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3 years ago

Solve the system of equation by elimination. 6x-3y=-21 4x=3y-9

Mathematics

1 answer:

dedylja [7]3 years ago

5 0

2x=-12 simplified, the expression or solving for X would be X=-6

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Analyze the diagram below and complete the instructions that follow.

Drupady [299]

Answer:

Step-by-step explanation:

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4 years ago

Question in the picture!!!

Dmitriy789 [7]

Answer:

140ft.^2

Step-by-step explanation:

3.5 x 4 = 14 (the width)

2.5 x 4 = 10 (the length)

- to find the area of the rectangle, you multiply the width and length

14 x 10 = 140

if you need a more detailed explanation i am free to give one!!

8 0

3 years ago

Solve and show work (4-9)(-6)-1)

Dmitry_Shevchenko [17]

The answer is 29.
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6 0

3 years ago

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Jared has total of 16 coins in his piggy bank consisting of only quarters and dimes the total value of all those coins is $3.10

4vir4ik [10]

The answer to the question

4 0

4 years ago

A farmer has a collapsable grain bag which can expand both vertically and horizontally as he needs it to. He wants to find a fun

bija089 [108]

Answer:

$3x^{3}+15x^{2}+x+5$

Step-by-step explanation:

We are told that the area of the bag can be represented by the function $f(x)=3x^{2} +1$ and as the bag is raised up its height can be represented by the function $g(x)=x +5$ .

Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.

$\text{Volume of collapsible bag}=f(x)*g(x)$

$\text{Volume of collapsible bag}=(3x^{2}+1)*(x +5)$

After using distributive property we will get,

$\text{Volume of collapsible bag}=3x^{2}(x+5)+1(x+5)$

$\text{Volume of collapsible bag}=3x^{3}+15x^{2}+x+5$

Therefore, the collapsible bag can hold $3x^{3}+15x^{2}+x+5$ grain.

6 0

4 years ago