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3 years ago

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A certain forest covers an area of 4200km2 Suppose that each year this area decreases by 5% What will the area be after 10 years

?
Use the calculator provided and round your answer to the nearest square kilometer.

1 answer:

Ne4ueva [31]3 years ago

7 0

Each year 1 - 5% = 95% of the acreage survives.

A(10) = 4500*0.95^10 = 2694.32

Answer: 2694.32

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Mean = 1.57

Variance=0.31

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To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

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4) Both surgeries are unsuccessful (X=0).

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$M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57$

The variance can be calculated as:

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2 years ago

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<span>v(x)=(s/t)
= (3x - 6) / (-3x+6)
= [3(x-2)] / [-3(x-2)] --> 3 is factored out
= 1/-1 </span>---> common terms are cancelled out.
= -1 ---> This is the simplified formula.

To find the domain, we equate the denominator to 0.
-3x+6 = 0
3x = 6
x = 2
Domain: all values except 2.

w(x)=(t/s)(x)
= (-3x+6)x / (3x-6)
= [-3x(x-2)] / [3(x-2)] --> 3 is factored out
= -x --> The common terms are cancelled out. This is the simplified formula.

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