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3 years ago

11

Container A (with volume 1.23 L) contains a gas under 3.24 atm of pressure. Container B (with volume

1 answer:

kolbaska11 [484]3 years ago

8 0

Now that a lot of pressure

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Eq-43 which type of fire extinguisher should be onboard a vessel with a permanently installed fuel tank

liq [111]

I think a type B fire extinguisher should be on board a vessel with a permanently installed fuel tank.
All vessels are required to have a type B fire extinguisher on board if one or more of the following conditions exists. That is; Inboard engine, vessel length of 26 feet or longer, enclosed living spaces, closed storage compartments in which flammable or combustible materials may be stored, permanently installed fuel tanks, and also closed compartments where portable fuel tanks may be stored.

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3 years ago

Ionic formula for ethanoate ion

statuscvo [17]

Nomenclature and common formula. When part of a salt, the formula of the acetate ion is written as CH3CO2−, C2H3O2−, or CH3COO−. Chemists abbreviate acetate as OAc− or, less commonly, AcO−. Thus, HOAc is the abbreviation for acetic acid, NaOAc for sodium acetate, and EtOAc for ethyl acetate.

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3 years ago

The concentration of a saturated BaCl2 solution is 1.75 M (mol/liter) and the concentration of a saturated Na2SO4 solution is 2.

Kitty [74]

Answer:

a) The theoretical yield is 408.45g of $BaSO_{4}$

b) Percent yield = $\frac{realyield}{408.45g}*100$

Explanation:

1. First determine the numer of moles of $BaCl_{2}$ and $Na_{2}SO_{4}$ .

Molarity is expressed as:

M= $\frac{molessolute}{Lsolution}$

- For the $BaCl_{2}$

M= $\frac{1.75molesBaCl_{2}}{1Lsolution}$

Therefore there are 1.75 moles of $BaCl_{2}$

- For the $Na_{2}SO_{4}$

M= $\frac{2.0moles[tex]Na_{2}SO_{4}$ }{1Lsolution}[/tex]

Therefore there are 2.0 moles of $Na_{2}SO_{4}$

2. Write the balanced chemical equation for the synthesis of the barium white pigment, $BaSO_{4}$ :

$BaCl_{2}+Na_{2}SO_{4}=BaSO_{4}+2NaCl$

3. Determine the limiting reagent.

To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:

- For the $BaCl_{2}$ :

$\frac{1.75}{1}=1.75$

- For the $Na_{2}SO_{4}$ :

$\frac{2.0}{1}=2.0$

As the $BaCl_{2}$ is the smalles quantity, this is the limiting reagent.

4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.

$1.75molesBaCl_{2}*\frac{1molBaSO_{4}}{1molBaCl_{2}}*\frac{233.4gBaSO_{4}}{1molBaSO_{4}}=408.45gBaSO_{4}$

5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:

Percent yield = $\frac{realyield}{theoreticalyield}*100$

Percent yield = $\frac{realyield}{408.45g}*100$

The real yield is the quantity of barium white pigment you obtained in the laboratory.

7 0

3 years ago

Plss answer the question in the picture. If you actually answer I will give you brainilest!!!

DedPeter [7]

Answer:

hey :)

your answer is D.

Explanation:

To find density, you must divide mass and volume.

8 divided by 4 is 2

6 divided by 6 is 0

4 divided by 2 is 2

hope i helped any :))

6 0

3 years ago

How do i solve it and what is the answer?

Masja [62]

Umm there’s no picture

6 0

3 years ago