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4 years ago

14

24 grams of magnesium metal reacts with 16 grams of oxygen gas to form magnesium oxide according to the law of conservation of m

ass how much magnesium oxide will there be after the chemical change is complete

1 answer:

galina1969 [7]4 years ago

8 0

X,,s,smells,s,wow,masks,as,mw

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I need help with this question 20 points and brainiest if ur right

Nutka1998 [239]

Answer:

The volume is 8 cm³

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3 years ago

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Question 6 A certain ionic compound has a solubility in water of at . Calculate the greatest mass of that could be dissolved in

emmainna [20.7K]

Complete Question:

A certain ionic compound X has a solubility in water of .765g/ml at 5 degrees C. Calculate the mass of X that's dissolved in 3 L of a saturated solution of X in the water at this temp. Be sure your answer has the correct unit symbol and significant digits.

Answer:

2.29 kg

Explanation:

A saturated solution is a solution that has the maximum amount of solute diluted at it, so if more solute is added, it will precipitate. The solutions can also be unsaturated (when more solute can be dissolved) or supersaturated (when there is more solute dissolved than the maximum. It's a very unstable solution).

The saturation is measured by the solubility, which indicates how much mass of the solute can be added to a certain volume of the solvent. So, the solubility (S) is the mass (m) divided by the volume (V).

For a solution with 3 L = 3000 mL,

S = m/V

0.765 = m/3000

m = 3000 * 0.765

m = 2295 g

m = 2.29 kg

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3 years ago

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alexgriva [62]

Answer:

The right answer to this is (b)

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3 years ago

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A. Find the pH and pOH of a solution having 6.6 x 10-6 M

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3 years ago

Calculate the solubility (in mol/L) of Fe(OH)3 (Ksp = 4.0 x 10^-38) in each of the following situations:

netineya [11]

Answer:

(A) 1.962x10^-10 M solubility in pure water

(B) 4.0 x 10^-33 M solubility

(C) 4.0 x 10^-27 M solubility

Explanation:

(A) Fe(OH)3 would give (Fe3+) and (3OH-)

Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

Let y = [Fe^3+]

Let 3y = [OH-]

4x10^-38 = (y)(3y)^3

4x10^-38 = 27y^4

y^4 = 4x10^-38 ÷ 27

y^4 = 1.481 x 10^-39

y = 1.962x10^-10 M solubility in pure water

(B) pH = 5.0

5.0 = - log [OH-]

-5.0 = log [OH-]

[OH-] = 10^-5.0 = 1.0 x 10^-5 M

So, Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

[Fe^3+][1.0 x 10^-5] = 4.0 x 10^-38

[Fe^3+] = 4.0 x 10^-38 ÷ 1.0 x 10^-5

= 4.0 x 10^-33 M solubility

(C) pH = 11.0

11.0 = - log [OH-]

-11.0 = log [OH-]

[OH-] = 10^-11.0 = 1.0 x 10^-11 M

So, Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

[Fe^3+][1.0 x 10^-11] = 4.0 x 10^-38

[Fe^3+] = 4.0 x 10^-38 ÷ 1.0 x 10^-11

= 4.0 x 10^-27 M solubility

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3 years ago