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3 years ago

Large objects that form dense gravity wells in place PLZ HELP ME !

1 answer:

6 0

A gravity well is the pull of gravity that a large body in space exerts. The larger the body (the more mass) the more of a gravity well it has. The Sun has a large (or deep) gravity well. Asteroids and small moons have much shallower gravity wells. Anything on a planet or moon is considered to be at the bottom of the gravity well. Entering space from the surface of a planet or moon means climbing out of the gravity well, something that often takes a huge amount of energy. The larger a planet or moon's gravity well is, the more energy it takes to achieve escape velocity and blast a ship off of it.

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What is the number of solute particles dissolved in water

iVinArrow [24]

It’s a big amount of it

7 0

3 years ago

Lead(II) nitrate is added slowly to a solution that is 0.0800 M in CT ions. Calculate the concentration of Pb2+ ions (in mol/L)

charle [14.2K]

Answer : The concentration of $Pb^{2+}$ ion is 0.0375 M.

Explanation :

The balanced equilibrium reaction will be:

$Pb^{2+}+2Cl^-\rightleftharpoons PbCl_2$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Pb^{2+}][Cl^-]^2$

Now put all the given values in this expression, we get:

$2.40\times 10^{-4}=[Pb^{2+}]\times (0.0800)^2$

$[Pb^{2+}]=0.0375M$

Therefore, the concentration of $Pb^{2+}$ ion is 0.0375 M.

8 0

3 years ago

What does the atomic number of an element represent?

harkovskaia [24]

Hello!
Whenever you see an atomic number with an element, you know the number of protons in the nucleus of the atom, which determines the chemical of an element and its place on the periodic table.

For example, Hydrogen has only one proton, however, if you were to add say 78 more protons, you'd get gold!

5 0

3 years ago

Read 2 more answers

If the value of Kc for the reaction is 2.50, what are the equilibrium concentrations if the reaction mixture was initially 0.500

ratelena [41]

Answer: The equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.

Explanation:

We are given:

Initial concentration of sulfur dioxide = 0.500 M

Initial concentration of nitrogen dioxide = 0.500 M

Initial concentration of sulfur trioxide = 0.00500 M

Initial concentration of nitrogen monoxide = 0.00500 M

The chemical reaction follows:

$SO_2+NO_2\rightleftharpoons SO_3+NO$

Initial: 0.500 0.500 0.005 0.005

At eqllm: 0.500-x 0.500-x 0.005+x 0.005+x

The expression of equilibrium constant for the above reaction follows:

$K_c=\frac{[SO_3][NO]}{[SO_2][NO_2]}$

We are given:

$K_c=2.50$

Putting values in above equation, we get:

$2.50=\frac{(0.005+x)\times (0.005+x)}{(0.500-x)\times (0.500-x)}\\\\x=0.304,1.37$

Neglecting the value of x = 1.37, because change cannot be greater than the initial concentration

So, equilibrium concentration of sulfur dioxide = $(0.500-x)=(0.500-0.304)=0.196M$

Equilibrium concentration of nitrogen dioxide = $(0.500-x)=(0.500-0.304)=0.196M$

Equilibrium concentration of sulfur trioxide = $(0.00500+x)=(0.00500+0.304)=0.309M$

Equilibrium concentration of nitrogen monoxide = $(0.00500+x)=(0.00500+0.304)=0.309M$

Hence, the equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.

4 0

3 years ago

How many grams of salt(NaCl) are in 4.8 moles?

Dafna11 [192]

Molar mass of salt = 58.44 grams/mole

$m = 58.44 \frac{g}{mol} \times 4.8mol = 280.512g$

5 0

3 years ago