The orbitals closest to the nucleus is the orbital wih the lowest energy. This is according to the basic rules stating that the energy of the shells as its principal quantum number increases, also increases. Thus the answer in 1 is B. Valence electrons are found in the outermost electron shell, on the other hand.
Answer:
<h2>The answer you are looking for is (B)</h2>
Explanation:
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Atomic number is less than 11
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Answer:
2a. If the temperature is increased, the reaction will shift to the right in an attempt to release some of the heat. As the forward reaction loses heat while the reverse would create more heat.
2b. If the pressure is increased, it would shift to the left to counteract the increase in pressure as the left side will have fewer molecules.
2c. If Cl2 is added the reaction will shift to the left in order to remove the stress of the extra Cl2 and favor the production of more reactant.
2d. If PCl3 is removed, the reaction will shift to the right. When part of the equation is removed the reaction learns to adapt to the loss by trying to make more Pcl3 and counteract the effects of losing the PCl3.
3a. The reaction will shift to the right to produce more heat and counter the negative effects of losing the heat.
3b. It will shift to the left to get rid of the excess HCl being produced and form more reactant from the breakdown of the HCl.
3c. It would shift to the right in order to get rid of the excess form products from it.
3d. If pressure is decreased there will be no effect on the shift of the reaction because there is an even amount of moles of gas on each side.
4a. K=[N2O4(g0] / [NO2(g)]2
4b. (Below)
K=[N2O4(g)] / [NO2(g)]2
0.4 / 0.5(2)
0.4/0.25 = 1.6
Keq= 1.6
