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katrin2010 [14]
3 years ago
11

A quantity of 200 mL of 0.862 M HCl (aq) is mixed with 200 mL of 0.431

Chemistry
1 answer:
Agata [3.3K]3 years ago
7 0

Answer:

The answer to this question has been described in details on the screenshots attached to this question.

Thanks. Hope it helps

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The element antimony has an atomic weight of 122 and consists of two stable isotopes antimony-121 and antimony-123. the isotope
grin007 [14]

Answer:-  123 amu.

Solution:- The formula to calculate the average atomic mass of an atom is:

Average atomic mass = mass of first isotope(abundance of first isotope) + mass of second isotope(abundance of second isotope)

Note: The percent abundance is converted to decimals.

mass of Sb-121 is 121 amu and it's percent abundance is 57.3% and in decimal it is 0.573. Percent abundance of Sb-123 is 42.8% and in decimal it is 0.428. We are asked to calculate it's mass. The average atomic mass of Sb is given as 122.

Let's say the mass of Sb-123 is M and  plug in the values in the formula and do calculations:

122 = 121(0.573) + M(0.428)

122 = 69.333 + M(0.428)

On rearrangement:-

M(0.428) = 122 - 69.333

M(0.428) = 52.667

M=\frac{52.667}{0.428}

M = 123

So, the mass of Sb-123 is 123 amu.

6 0
4 years ago
For a half-reaction in an acidic solution, which substances should you add to balance the equation?
Alla [95]
The answer is a. H+ and H2O. For a half-reaction in acidic solutions, elements that are not hydrogen and oxygen are balanced first. Then we add H2O to balance oxygen atoms and we add H+ to balance the hydrogen atoms. We do the same steps for basic solutions, but we also add hydroxide ions OH- in the latter part.
8 0
3 years ago
Explain how temperature and precipitation are affected by latitude and the sun's rays.
Contact [7]
Latitude and Temperature

At the equator, the Sun's rays are most direct. This is where temperatures are highest. At higher latitudes, the Sun's rays are less direct. The farther an area is from the equator, the lower its temperature.
8 0
3 years ago
Read 2 more answers
What would be the mass in grams of 8.94 x 10 22 formula units of copper(II) fluoride, CuF 2
Nadya [2.5K]

The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g

<h3>Avogadro's hypothesis </h3>

6.02×10²³ formula units = 1 mole of CuF₂

But

1 mole of CuF₂ = 101.5 g

Thus,

6.02×10²³ formula units = 101.5 g of CuF₂

<h3>How to determine the mass of 8.94×10²² formula units of CuF₂</h3>

6.02×10²³ formula units = 101.5 g of CuF₂

Therefore,

8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³

8.94×10²² formula units = 15.07 g of CuF₂

Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂

Learn more about Avogadro's number:

brainly.com/question/26141731

#SPJ1

5 0
2 years ago
At 35°C, Kc = 1.6 multiplied by10-5 for the following reaction
Brums [2.3K]

Answer : The equilibrium concentrations of all species NO,Cl_2\text{ and }NOCl are, 0.05 M, 0.043 M and 0.975 M respectively.

Explanation : Given,

Moles of  NO = 2 mole

Moles of  Cl_2 = 1 mole

Volume of solution = 1 L

Initial concentration of NO = 2 M

Initial concentration of Cl_2 = 1 M

The given balanced equilibrium reaction is,

                            2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

Initial conc.          2 M            1 M            0

At eqm. conc.    (2-2x) M   (1-x) M         (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NOCl]^2}{[NO]^2[Cl_2]}

The K_c for reverse reaction = \frac{1}{1.6\times 10^{-5}}

Now put all the given values in this expression, we get :

\frac{1}{1.6\times 10^{-5}}=\frac{(2x)^2}{(2-2x)^2\times (1-x)}

By solving the term 'x', we get :

x = 0.975

Thus, the concentrations of NO,Cl_2\text{ and }NOCl at equilibrium are :

Concentration of NO = (2-2x) M  = (2 - 2 × 0.975) M = 0.05 M

Concentration of Cl_2 = (1-x) M = 1 - 0.975 = 0.043 M

Concentration of NOCl = x M = 0.975 M

Therefore, the equilibrium concentrations of all species NO,Cl_2\text{ and }NOCl are, 0.05 M, 0.043 M and 0.975 M respectively.

6 0
3 years ago
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