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2 years ago

Global winds are directly caused by the Earth's rotation and

Chemistry

1 answer:

nordsb [41]2 years ago

6 0

Answer:

The uneven heating of Earth's surface

Explanation:

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According to the selection, what is the main weakness of the tortoise?<br>

Agata [3.3K]

Answer:

Nose

Explanation:

Because every time I touch it's nose, it will hide itself into the shell faster than other places

8 0

3 years ago

A pH change can be evidence that

drek231 [11]

Answer:

Explanation:

The acid level has changed

3 0

3 years ago

Chloroform is a liquid once used for anesthetic. What is the volume of 5.0 g of chloroform? The density of chloroform 1.49 g/mL

mario62 [17]

Answer:

3.3557047 mL

Explanation:

The density can be found using the following formula:

$d=\frac{m}{v}$

Let's rearrange the formula to find the volume, $v$ .

$d*v=\frac{m}{v}*v$

$d*v=m$

$\frac{d*v}{d} =\frac{m}{d}$

$v=\frac{m}{d}$

The volume can be found by dividing the mass by the density. The mass of the chloroform is 5 grams and the density is 1.49 grams per milliliter. Therefore,

$m= 5g \\d= 1.49 g/mL$

Substitute the values into the formula.

$v=\frac{5g}{1.49 g/mL}$

Divide. When we divide, the grams, or g, in the numerator and denominator will cancel out.

$v= \frac{5}{1.49}mL$

$v=3.3557047 mL$

The volume of 5 grams of chloroform is 3.3557047 milliliters

4 0

3 years ago

Ka/KbMIXED PRACTICE108.Calculate the [H3O+(aq)], the pH, and the % reaction for a 0.50 mol/L HCN solution. ([H3O+(aq)] = 1.8 x 1

NeTakaya

Answer:

a) [H₃O⁺] = 1.8x10⁻⁵ M

b) pH = 4.75

c) % rxn = 3.5x10⁻³ %

Explanation:

a) The dissociation reaction of HCN is:

HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)

0.5 M - x x x

The dissociation constant from the above reactions is given by:

$Ka = \frac{[H_{3}O^{+}][CN^{-}]}{[HCN]} = 6.17 \cdot 10^{-10}$

$6.17 \cdot 10^{-10} = \frac{x*x}{(0.5 - x)}$

$6.17 \cdot 10^{-10}*(0.5 - x) - x^{2} = 0$

By solving the above quadratic equation we have:

x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]

Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.

b) The pH is equal to:

$pH = -log[H_{3}O^{+}] = -log(1.75 \cdot 10^{-5} M) = 4.75$

Then, the pH of the HCN solution is 4.75.

c) The % reaction is the % ionization:

$\% = \frac{x}{[HCN]} \times 100$

$\% = \frac{1.75 \cdot 10^{-5} M}{0.5 M} \times 100$

$\% = 3.5 \cdot 10^{-3} \%$

Therefore, the % reaction or % ionization is 3.5x10⁻³ %.

I hope it helps you!

6 0

2 years ago

Select the correct answer.

GREYUIT [131]

Answer:HNO3 + NaOH → H2O + NaNO3

Explanation:

8 0

3 years ago