Answer:
2
Step-by-step explanation:
Answer:
It would be the third answer
Step-by-step explanation:
Answer: 10 bags
Step-by-step explanation:
First we must calculate the field area. Assuming it is a rectangle then its area equals the product of its length times its width
You use 8 pounds of fertilizer per 1,000 square feet
So the amount of fertilizer you should use is:
As the fertilizer comes in bags of 50 pound then you need
Since you can not buy 9.2 bags then we round up to the next whole number.
Finally you need 10 bags of fertilizer
to solve this we need to isolate the x variable.
subtract 1 from each side: [3x+4] = 6
now we can drop the parentheses and subtract 4 from each side: 3x = 2
divide each side by 3: x = 2/3
Cos <span>2</span><span>x </span><span>= </span><span>2</span><span>cos^</span><span>2</span><span>(</span><span>x</span><span>) </span><span>− </span><span>1</span>
2<span>cos^</span><span>2 </span><span>(</span><span>x</span><span>) </span><span>− </span><span>1 </span><span>− </span><span>cos</span><span>(</span><span>x</span><span>) </span><span>≡ </span><span>2</span><span>cos^</span><span>2</span><span>(</span><span>x</span><span>) </span><span>− </span><span>cos</span><span>(</span><span>x</span><span>) </span><span>− </span><span>1</span>
Let <span>cos</span><span>(</span><span>x</span><span>) </span><span>= </span><span>y</span>
2<span>y^</span><span>2 </span><span>− </span><span>y </span><span>− </span><span>1
</span><span>(</span><span>2</span><span>y </span><span>+ </span><span>1</span><span>) </span><span>(</span><span>y </span><span>− </span><span>1</span><span>) </span>y <span>= </span><span>−</span><span>1/2
</span><span>y </span><span>= </span><span>1</span>
y <span>= </span><span>cos</span><span>(</span><span>x)</span>
∴ <span>cos</span><span>(</span><span>x</span><span>) </span><span>= </span><span>−</span><span>1/</span><span>2 ; </span><span>cos</span><span>(</span><span>x</span><span>) </span><span>= </span><span>1</span>
x <span>= </span><span>2/</span><span>3 </span><span>π ;</span><span> </span><span>x </span><span>= </span><span>0</span>
solutions;x <span>= </span><span>2/</span><span>3 </span><span>π</span><span>, </span><span>x </span><span>= </span><span>0</span><span>, </span><span>x </span><span>= </span><span>4/</span><span>3 </span><span>π</span><span>, </span><span>x </span><span>= </span><span>2</span><span>π</span>
