Answer is D because i add 21 and 27 and got 48 then divied by the total number sandwiches and got .80
Answer:
<h3>39.6</h3>
Step-by-step explanation:
collecting like terms we have:
5x-2x=-1+42
equating the terms..we have:
3x=41
divide both sides by the Co-efficient of x:
3x\3=42\3
x=39.6
Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So,
is 37°. We can see from the diagram that
would be
143°.
Also, the new bearing is N 25°E. So,
would be 25°.
Now we can find
. As the sum of the internal angle of a triangle is 180°.

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
4.25 yards
Step-by-step explanation:
Area of rectangle = Base x Height
or
Height = Area of Rectangle ÷ Base
In this case, Area =38.25 sq yards and Base = 9 yards
Height = 38.25 ÷ 9 = 4.25 yards
1: I can’t see one it’s cut out sorry :(
2:go down four horrizontal for each line making a rhombus
3: 3a:true 3b:true 3c:false 3D: false
4.PART A: Draw a square in the middle.
4. PART B: Say there are four right angles
5: Line, point, ray, line segment
6. There are 2 acute and 1 right
7. A B C
8: 1/4 1/6 1/8
9: 9a 9c and 9d
10: square and polygons first, then triangles because they have 4 sides while a triangle has 3
10 PART B: rectangles second, then the pentagons are third, the parallelogram is first, then the triangles because a rectangle has all right angles
11: she drew a square!
12: polygons without right angles
13: I can’t draw on your paper just draw three lines in the trapezoid
13: a c and d