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3 years ago

Which is smaller 1/6 or 1/5

2 answers:

5 0

1/6 because you are breaking something into 6 and you got to share think of it like that so you get a smaller piece than you cutting it into 1/5...... so the answer is 1/6

Murrr4er [49]3 years ago

4 0

1/6 is smaller because
1/6=5/30
1/5=6/30 and 6/30 is greater

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Answer:

The slope is zero.

Step-by-step explanation:

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3 years ago

A radio station requires DJs to play 2 commercials for every 10 songs they play.What is the unit rate of songs to commercial?

slavikrds [6]

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3 years ago

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3 years ago

The bike store marks up the wholesale cost of all of the bikes they sell by 30%.

aev [14]

Answer:

A ) The money which Andre pay for the bike is $ 67.30

B ) The money which Andre pay for the bike is $ 76.92

Step-by-step explanation:

Given as :

The wholesale cost or market price of the bike = m.p = $ 96.15

A ) The discount percentage = 30 %

Let The selling price of the bike after discount = s.p

Now ,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 30 % = 1 - $\dfrac{s. p }{m . p}$

or, $\dfrac{30 }{100}$ = 1 - $\dfrac{s. p }{96.15}$

Or, $\dfrac{s. p }{96.15}$ = 1 - $\dfrac{30 }{100}$

or, $\dfrac{s. p }{96.15}$ = $\dfrac{100 - 30 }{100}$

Or, $\dfrac{s. p }{96.15}$ = $\dfrac{70}{100}$

Or, s. p = $\dfrac{70}{100}$ × 96.15

∴ s.p = $ 67.305

So, He will pay $ 67.30

Hence The money which Andre pay for the bike is $ 67.30 . Answer

B ) If the bike is discounted by 20 % , let The selling price = s.p'

So,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 20 % = 1 - $\dfrac{s. p' }{m . p}$

or, $\dfrac{20 }{100}$ = 1 - $\dfrac{s. p' }{96.15}$

Or, $\dfrac{s. p' }{96.15}$ = 1 - $\dfrac{20 }{100}$

or, $\dfrac{s. p' }{96.15}$ = $\dfrac{100 - 20 }{100}$

Or, $\dfrac{s. p' }{96.15}$ = $\dfrac{80}{100}$

Or, s. p' = $\dfrac{80}{100}$ × 96.15

∴ s.p' = $ 76.92

So, He will pay $ 76.92

Hence The money which Andre pay for the bike is $ 76.92 . Answer

7 0

3 years ago

What is the distance between A (-4,2) and B (12,4)

My name is Ann [436]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad
B(\stackrel{x_2}{12}~,~\stackrel{y_2}{4})\qquad \qquad
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AB=\sqrt{[12-(-14)]^2+[4-2]^2}\implies AB=\sqrt{(12+14)^2+(4-2)^2}
\\\\\\
AB=\sqrt{26^2+2^2}\implies AB=\sqrt{680}$

3 0

3 years ago

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