Answer:
0.0827M of H₂SO₃
Explanation:
LiOH reacts with H₂SO₃ to produce water and Li₂SO₃, thus:
2LiOH + H₂SO₃ → 2H₂O + Li₂SO₃
<em>Where 2 moles of lithium hydroxide react with 1 mole of sulfurous acid.</em>
As the chemist requires 22.14mL = 0.02214L of a 0.210M solution to neutralize the acid, moles of LiOH are:
0.02214L × (0.210mol / L) =<em>0.004649 moles of LiOH</em>.
As 2 moles of LiOH react with 1 mole of H₂SO₃, moles of H₂SO₃ are:
0.004649 moles of LiOH ₓ (1 mole H₂SO₃ / 2 mol LiOH) =
<em>0.002325 moles of H₂SO₃</em>
These moles are present in 28.10mL = 0.02810L. Thus, molar concentration of the acid is:
0.002325 moles H₂SO₃ / 0.02810L = <em>0.0827M of H₂SO₃</em>
Answer:
50 mL
Explanation:
We can solve this problem by using Boyle's Law, which states that:
"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"
Mathematically:
where
p is the pressure of the gas
V is the volume of the gas
The equation can be rewritten as
where in this problem:
is the initial pressure of the gas in the coke
is the initial volume
is the final pressure
Solving for V2, we find the final volume:
The mass is 132.0384 grams.
1) Molar mass C8H9NO2
Element Atomic mass # of atoms mass
g/mol g
C 12 8 12*8 = 96
H 1 9 1*9 = 9
N 14 1 14*1 = 14
O 16 2 16*2 = 32
molar mass = 96 + 9 + 14 + 32 = 151 g/mol
2) Number of mols in a tablet
# of moles = mass / molar mass = 0.500 g / 151 g/mol = 0.003311 moles
3) 3 doses * 2 tablets * 0.003311 moles / tablet = 0.020 moles
