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Shkiper50 [21]
3 years ago
9

2. Convert 1500 milligrams to grams.​

Chemistry
1 answer:
Kisachek [45]3 years ago
7 0

Answer: 1.5 grams.

Explanation:

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The four fundamental forces are arranged in the increasing order of their relative strength.
natali 33 [55]

Answer:

The correct answer is - both act only between non-atomic particles.

Explanation:

The decreasing order of their relative strength is - the strong force, electromagnetism, weak force, gravity.

so, A would be here = gravity

B would be  = weak force

C  would be = strong force

The weak and strong forces both are fundamental forces that act on sub-atomic particles only such as quarks.

3 0
3 years ago
How many atoms are present in 0.35 mol of carbon dioxide?
STatiana [176]
0.35 moles carbon dioxide (6.022 X 10^23/1 mole CO2) = 2.1 X 10^23 atoms of
<span> carbon dioxide </span>
6 0
3 years ago
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PLS I NEED HELP ASAP! BRAINLIEST TO FULL ANSWER!!
Serggg [28]

Answer:

CARBON HYDROGEN NYTROGEN OXYGEN

Explanation:

POGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOG

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The addition of 0.242 L of 1.92 M KCl to a solution containing Ag+ and Pb2+ ions is just enough to precipitate all of the ions a
kolezko [41]

Answer:

Mass PbCl₂ = 50.24g

Mass AgCl = 14.84g

Explanation:

The addition of Cl⁻ ions from the KCl solution results in the precipitation of AgCl and PbCl₂ as follows:

Ag⁺ + Cl⁻ → AgCl(s)

Pb²⁺ + 2Cl⁻ → PbCl₂(s)

If we define X as mass of PbCl₂, moles of Cl⁻ from PbCl₂ are:

Xg × (1mol PbCl₂/ 278.1g) × (2moles Cl⁻ / 1 mole PbCl₂) = <em>0.00719X moles of Cl⁻ from PbCl₂</em>

<em />

And mass of AgCl will be 65.08g-X. Moles of Cl⁻ from AgCl is:

(65.08g-Xg) × (1mol AgCl/ 143.32g) × (1mole Cl⁻ / 1 mole AgCl) = <em>0.45409 - 0.00698X moles of Cl⁻ from AgCl</em>

<em />

Moles of Cl⁻ that were added in the KCl solution are:

0.242L × (1.92mol KCl / L) × (1mole Cl⁻ / 1 mole KCl) = 0.46464 moles of Cl⁻ added.

<em />

Moles Cl⁻(AgCl) + Moles Cl⁻(PbCl₂) = Moles Cl⁻(added)

0.45409 - 0.00698X moles + (0.00719X moles) = 0.46464 moles

0.45409 + 0.00021X = 0.46464

0.00021X = 0.01055

X = 0.01055 / 0.00021

X = 50.24g

As X = Mass PbCl₂

<h3>Mass PbCl₂ = 50.24g</h3>

And mass of AgCl = 65.08 - 50.24

<h3>Mass AgCl = 14.84g</h3>

6 0
4 years ago
Explain how the parts of a wave are affected by the changes in amplitude and pitch
maw [93]
Waves propagating through material medium the amplitude of the waves decides the intensity of the waves as intensity is directly proportional to the square of its amplitude.

5 0
3 years ago
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