2. Convert 1500 milligrams to grams.

Hydrogen reacts with iodine to form hydrogen iodide: H2[g] + 12[g] = 2H1[g] The

ELEN [110]

Answer:

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6 0

3 years ago

En que epoca aprendieron a trabaja el cobre y otros metales?

g100num [7]

Maybe if you put it in english i’ll answer.. nahh jp i’m fluent

6 0

2 years ago

What would you do to change a saturated solid/liquid solution to an unsaturated solution

Semenov [28]

Explanation:

Saturated solid/liquid solution is changed to an unsaturated solution by the dilution process.

When the saturated solution is diluted by addition large quantity of solvent it changed to an unsaturated solution.

Saturated solid/liquid solution can also be changed to an unsaturated solution by increasing the temperature or heating the solution.

A saturated solution is a solution where further solute will not dissolve in the solvent.

An unsaturated solution is a solution in which has the ability to dissolve more solute.

4 0

3 years ago

1. Write the balanced equation for the decomposition of hydrogen peroxide

earnstyle [38]

The balanced equation for the decomposition of hydrogen peroxide is H₂O₂(aq)→2H₂O(l)+O₂(g).

<h3>What is decomposition reaction?</h3>

Decomposition reactions are those reactions in which a compound will decompose into small molecules.

Hydrogen peroxide will decompose into water molecule and oxygen gas, balanced chemical equation will be represented as:

H₂O₂(aq) → 2H₂O(l) + O₂(g)

Where all atoms are present in equal quantities on both side of the equation.

Hence balanced decomposition reaction of H₂O₂ is H₂O₂(aq)→2H₂O(l)+O₂(g).

To know more about decomposition reaction, visit the below link:

brainly.com/question/27300160

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5 0

2 years ago

Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2

lapo4ka [179]

Answer: Concentration of $CO$ = 0.328 M

Concentration of $Cl_2$ = 0.328 M

Concentration of $COCl_2$ = 0.532 M

Explanation:

Moles of $CO$ and $Cl_2$ = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of $CO$ and $Cl_2$ = $\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M$

The given balanced equilibrium reaction is,

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.860M 0.860M 0

At eqm. conc. (0.860-x) M (0.860-x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get :

$4.95=\frac{x}{(0.860-x)^2}$

By solving the term 'x', we get :

x = 0.532 M

Thus, the concentrations of $CO,Cl_2\text{ and }COCl_2$ at equilibrium are :

Concentration of $CO$ = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of $Cl_2$ = (0.860-x) M = (0.860-0.532) M = 0.328 M

Concentration of $COCl_2$ = x M = 0.532 M

3 0

3 years ago

2. Convert 1500 milligrams to grams.​

2. Convert 1500 milligrams to grams.