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Colt1911 [192]
3 years ago
10

A chemist uses a standard solution of 0.210 M lithium hydroxide (LiOH) to titrate 28.10 mL of sulfurous acid acid (H2SO3), she f

inds that it requires 22.14 mL of the base to reach the end-point of the titration. What is the molarity of the acid solution? What is the concentration of H2SO3?
Your answer must be rounded to the correct number of significant figures. Be sure to specify a unit.
Chemistry
2 answers:
miv72 [106K]3 years ago
6 0

Answer:

M_{acid}=0.0827M

Explanation:

Hello,

In this case, we should consider the acid-base reaction between sulfurous acid and lithium hydroxide:

2LiOH+H_2SO_3\rightarrow Li_2SO3+2H_2O

Thus, we notice a 2:1 molar ratio between lithium hydroxide and sulfurous acid, for that reason, at the equivalence point we have:

2*n_{acid}=n_{base}

That in terms of concentrations and volumes is:

2*M_{acid}V_{base}=M_{base}V_{base}

Thus, we solve for the molarity of the acid which is sulfurous acid:

M_{acid}=\frac{M_{base}V_{base}}{2*V_{base}} =\frac{0.210M*22.14mL}{2*28.10mL}\\\\M_{acid}=0.0827M

Best regards.

erik [133]3 years ago
3 0

Answer:

0.0827M of H₂SO₃

Explanation:

LiOH reacts with H₂SO₃ to produce water and Li₂SO₃, thus:

2LiOH + H₂SO₃ → 2H₂O + Li₂SO₃

<em>Where 2 moles of lithium hydroxide react with 1 mole of sulfurous acid.</em>

As the chemist requires 22.14mL = 0.02214L of a 0.210M solution to neutralize the acid, moles of LiOH are:

0.02214L × (0.210mol / L) =<em>0.004649 moles of LiOH</em>.

As 2 moles of LiOH react with 1 mole of H₂SO₃, moles of H₂SO₃ are:

0.004649 moles of LiOH ₓ (1 mole H₂SO₃ / 2 mol LiOH) =

<em>0.002325 moles of H₂SO₃</em>

These moles are present in 28.10mL = 0.02810L. Thus, molar concentration of the acid is:

0.002325 moles H₂SO₃ / 0.02810L = <em>0.0827M of H₂SO₃</em>

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2. Transfer in energy to reach the highest amount of kinetic energy for both substance B and C.
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2 years ago
What type of reaction is shown below: Br2 + Kl 12 + KBr​
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Answer:Chemical reaction

Explanation:

The main concept that must be applied to determine the coefficients (amount of each item) is that there must be equal amounts of each element on each side of the equation. We are not destroying or creating new atoms. In this case, the unbalanced reaction formula is:

B

r

2

+

K

I

=

K

B

r

+

I

2

There are a two problems we need to solve before it will be balanced:

There are two moles of Iodine atoms (

I

) on the right side of the equation, while there is only one mole on the right side.

There are two moles of bromine (

B

r

) atoms on the left side, while there is only one on the right.

Since there are two moles of bromine atoms on the left side, we need two moles on the right as well. We can do this by adding a coefficient of two to the

'

K

B

r

'

term in the equation. Our now modified equation looks like this:

B

r

2

+

K

I

=

2

K

B

r

+

I

2

There is one mole of Iodine atoms on the left, and two on the right. To fix this, we add a coefficient of two to the

'

K

I

'

term. The resulting equation is below.

B

r

2

+

2

K

I

=

2

K

B

r

+

I

2

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1

B

r

2

+

2

K

I

=

2

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B

r

+

1

I

2

Can you see that there is now an equal amount of each element on each side of the equation? That means that it is balanced.

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3 years ago
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Answer:

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1. 40g per mole

2. 19g per mole

3. 64g per mole

4. 32 g per mole

5. 17g per mole

6. 59.5g per mole

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8.220g per mole

9. 78g per mole

10. 200g per mole

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