Answer:
The dimensions of constant C are of ![[L^{3}T]^{-4}](https://tex.z-dn.net/?f=%5BL%5E%7B3%7DT%5D%5E%7B-4%7D)
Step-by-step explanation:
It is given that

Since the dimensions of volume are ![[L^{3}]](https://tex.z-dn.net/?f=%5BL%5E%7B3%7D%5D)
Each of the term shall have a dimension of
since they are in addition.
Thus for third term we can write
Thus we have
![[L^{3}]=[C][T^{4}]\\\\\therefore [C]=[L^{3}][T^{-4}]](https://tex.z-dn.net/?f=%5BL%5E%7B3%7D%5D%3D%5BC%5D%5BT%5E%7B4%7D%5D%5C%5C%5C%5C%5Ctherefore%20%5BC%5D%3D%5BL%5E%7B3%7D%5D%5BT%5E%7B-4%7D%5D)
Answer:

Step-by-step explanation:

Answer:
Step-by-step explanation:
Given function is h(t) = -16t² + 1500
a). For h(t) = 1000 feet,
1000 = -16t² + 1500
1000 - 1500 = -16t² + 1500 - 1500
-500 = -16t²
t² = 
t = 
t = 5.59 sec
b). For h(t) = 940 feet,
940 = -16t² + 1500
940 - 1500 = -16t² + 1500 - 1500
-16t² = -560
t² = 
t = 
t = 5.92 sec
c). For domain and range of the function,
When the jumper comes down to the ground,
h = 0
0 =-16t² + 1500
t² = 
t = 
t = 9.68 sec
Since, x-values on the graph vary from x = 0 to x = 9.68,
Domain : [0, 9.68]
Vertex of the quadratic function: (0, 1500)
Since, coefficient of the highest degree term is negative, parabola will open downwards.
Therefore, y-values of the function will vary in the interval y = 0 to y = 1500
Range: [0, 1500]
3/22 but in a decimal 0.1363
Answer:
1/12 5/12 11/12
Step-by-step explanation:
Um it was pretty obvious but...