What is s-c=m? Solve for c

Determine the point (x,y) ( x , y ) on the unit circle associated with the following real number s. Write the exact answer as an

Harlamova29_29 [7]

The required coordinates of the unit circle for s = -11π/6 is (√3/2, 1/2). Using trigonometric functions, the required answer is calculated.

<h3>What are the trigonometric functions?</h3>

There are six trigonometric functions.

They are sin θ, cos θ, tan θ, sec θ, cosec θ, and cot θ.

Where θ - 0 to 360° or 0 to 2π

<h3>Calculation:</h3>

For a unit circle, the coordinates are given in the form of trigonometric functions as below:

x = cos θ and y = sin θ

Here it is given that s = θ = -11π/6

So, on substituting,

x = cos θ = cos (-11π/6)

⇒ x = √3/2

y = sin θ = sin (-11π/6)

⇒ y = 1/2

Thus, the required coordinate pair is (√3/2, 1/2).

Learn more about trigonometric functions here:

brainly.com/question/2291993

#SPJ1

7 0

10 months ago

At 5.45p.M .,lixin,khairul and Devil are at the starting point of a 1-km circular path. Lixin Takes 18 minutes to walk one round

sweet [91]

Answer:

$Meeting\ Time = 6:03\ pm$

Step-by-step explanation:

Given

$Start\ Time= 5:45pm$

$Lixin = 18\ min/round$

$Khairul = 360\ seconds/round$

$Devi = 4minutes/2\ rounds$

Required

Determine their next meeting time

First, we need to get their unit rate in minutes per round

$Lixin = 18\ min/round$

$Khairul = 360\ seconds/round$

Convert 360 seconds to minutes

$Khairul = \frac{360}{60} min/round$

$Khairul = 6 min/round$

$Devi = 4minutes/2\ rounds$

Divide by 2/2

$Devi = 2mins/round$

So, we have:

$Lixin = 18\ min/round$

$Khairul = 6 min/round$

$Devi = 2mins/round$

Next, is to determine the LCM of 18, 6 and 2

$18=2 * 3 * 3$

$6 = 2 * 3$

$3 = 3$

Their LCM is:

$LCM = 2 * 3 * 3$

$LCM = 18$

This means that they will meet 18 minutes after their initial time of departure.

So:

$Meeting\ Time = 5:45\ pm + 18\ minutes$

$Meeting\ Time = 6:03\ pm$

3 0

2 years ago

Please help, would be greatful :)

tankabanditka [31]

Answer:

x ≈ 25.5°

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

<u>Trigonometry</u>

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Angle θ = <em>x</em>°

Opposite Leg = 10

Hypotenuse = 21

<u>Step 2: Solve for </u><em><u>x</u></em>

Substitute [tangent]: tanx° = 10/21
Inverse trig: x° = tan⁻¹(10/21)
Evaluate: x = 25.4633°
Round: x ≈ 25.5°

8 0

2 years ago

A jar contains 2 red and 4 blue marbles. A marble is drawn from the jar. What is the probability that a red marble will be drawn

allsm [11]

Salutations!

<span>A jar contains 2 red and 4 blue marbles. A marble is drawn from the jar. What is the probability that a red marble will be drawn?

So lets solve this!

Probability is an event of chance; an occurrence of chance.

The probability that a red marble will be drawn is 2/6

Simply 2/6 which is 1/3

Thus, your answer is option C.

Hope I helped :D
</span>

5 0

3 years ago

Read 2 more answers

A girl's feet are negative 2 over 4 yards from the surface of a pool. A boy's feet are negative 3 over 4 yards from the surface

frozen [14]

The girls are closer. Her feet are 1/2 the distance away from the surface pool, the boys are 3/4 away.

6 0

2 years ago