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3 years ago

Quadrilateral CDEF is a rhombus. What is ECF?

Mathematics

1 answer:

romanna [79]3 years ago

4 0

Answer:

Step-by-step explanation:

∠ECF=\frac{1}{2}(180-114)=\frac{1}{2}(66)=33°

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Fins the quontient 5)47 and it has to have a remander plzzzzzzzz help meeeee!!!!!!;

timama [110]

See how many 5s there are in 47? There are 9 and also a leftover 2 which is your remainder.<span />

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3 years ago

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Please help I will mark brainliest!!!!!!!!!!

Oxana [17]

Answer:

9/10 pounds

Step-by-step explanation:

3/5 × 1 1/2

= 9/10

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3 years ago

Which is equation of an ellipse of an ellipse with directrices at x=4 and foci at (2,0) (-2,0)

r-ruslan [8.4K]

Answer:

$\frac{x^2}{8} + \frac{y^2}{4}=1$

Step-by-step explanation:

The directrices in this case are vertical lines, so we have a horizontal ellipse. The equation for that ellipse is:

$\frac{(x - h)^2}{a^2} + \frac{(y-k)^2}{b^2}=1$

The center of the ellipse is (h,k), the diretrix is x = d and the foci are given by (h+c, k) and (h-c, k)

So, comparing the foci, we have that k = 0 and:

$h + c = 2$

$h - c = -2$

Adding these two equations, we have:

$2h = 0$

$h = 0$

$c = 2$

We can find the value of a^2 using the property:

$c / a = a / d$

Using c = 2 and d = 4, we have:

$a^2 = c * d$

$a^2 = 8$

Now, to find b^2, we use the property:

$a^2 = b^2 + c^2$

$8 = b^2 + 4$

$b^2 = 4$

So the equation of the ellipse is:

$\frac{x^2}{8} + \frac{y^2}{4}=1$

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3 years ago

Solve plz.....................................................................................

kirill115 [55]

The answer is c)4
hope it will help u

8 0

3 years ago

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Choose the equation below that represents the line that passes through the point (7, -2) and has a slope of -3

Ray Of Light [21]

Answer:

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - 3 and (a, b) = (7, - 2 ), thus

y - (- 2) = - 3(x - 7) , that is

y + 2 = - 3(x - 7) → B

3 0

3 years ago

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