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3 years ago

What does it mean if there are two different alleles for a trait?

2 answers:

8 0

If there are two different alleles for a trait, this means t<span>he trait could show up in two different forms.</span>

velikii [3]3 years ago

8 0

Answer:

The correct answer would be B. The trait could show up in two different forms.

Alleles refer to the alternative forms of the gene. Different alleles of a gene code for different traits in an organism.

For example, T codes for tallness and t codes for a dwarf. Similarly, R codes for round seed shape and r codes for wrinkled seed shape et cetera.

Based on the expression levels, the alleles can be of two types recessive and dominant.

The allele which expresses itself in a heterozygous condition is said to be a dominant allele and the allele which is masked in heterozygous condition is said to be a recessive allele.

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How are traits inherited?

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3 years ago

What is the difference between diffusion and facilitated diffusion?

Feliz [49]

Answer:

Diffusion is the movement of molecules from an area where the molecule is in high concentration to an area where the molecule is in lower concentration. ... Facilitated diffusion is the movement of a molecule from an area of high concentration to an area of lower concentration with the help of a protein channel or carrier.

Explanation:

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2 years ago

small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi

irina [24]

Answer:

Frequency of p $= 0.684$

Frequency of p $= 0.316$

Number of individuals with homozygous dominant (AA) $= 47$

Number of individuals with heterozygous (Aa) $= 43$

Number of individuals with homozygous recessive (aa) $= 10$

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals $(q^{2})$ is $\frac{10}{100} = 0.1$

Now, q will be

$= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316$

As per Hardy Weinberg's equation -

$p + q = 1$

Substituting the value of q in above equation, we get -

$p + 0.316 = 1p = 1 -0.316\\p = 0.684$

Now the frequency of homozygous dominant (AA) will be

$p^{2} = 0.684^{2} \\= 0.467$

Hence, out of 100 people $0.467 * 100 = 46.7 or 47$ people are homozygous dominant (AA)

Like wise out of 100 people $0.1 * 100 = 10$ people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

$p^{2} + q^{2} + 2pq = 1\\$

Substituting the values in above equation, we get -

$0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433$

So, out of 100 people $0.433 * 100 = 43.3 or 43$ people are heterozygous (Aa)

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3 years ago

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Alex73 [517]

The correct option is D.

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2 years ago

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