Answer:
<em>615.44m²</em>
Step-by-step explanation:
The base of the silo is a circle
Rea of the base of the silo = πr²
r is the radius of the silo
Given
radius r = 14m
Area of the base of the silo = π(14)²
Area of the base of the silo = 3.14(196)
Area of the base of the silo = 615.44
<em>Hence the area of the base of the silo is 615.44m²</em>
Answer:
They say that the sum of the two numbers (x and y) is 64, so we can write our first equation by adding them and setting that sum equal to 64:
x + y = 64
The question also tells us that their difference is 14. Similarly to before, we'll just subtract the two numbers and set that difference equal to 14:
x - y = 14
Now from here, you know how to continue with substitution to find the values for x and y. Just remember when you get a word problem to break it down and look for key words like sum, difference, or product, and from there you'll be able to build your system of equations.
A. you plug in to a calculator, which will give 1840.986 so you need to round up to 1840.99. if you truncate it to .98 then he won't reach 2000 in 3 years
b. for this one if you look at the equation given to find the principle it is principle = result (1+rate) ^ -time
if you re arrange this you get result=principle (1+rate)^time
so result = 1840.99(1.028)^5
= 2113.57
Answer:
C
Step-by-step explanation:
The red graph is the graph of y = f(x) shifted 1 unit right and then reflected in the x- axis.
Given y = f(x) then f(x + a) is a horizontal translation of a units
• If a > 0 then shift to the left of a units
• If a < 0 then shift to the right of a units
Here shift to the right of 1 unit, thus
y = f(x - 1)
Under a reflection in the x- axis
a point (x, y ) → (x, - y )
Note the y- coordinates are the negative of each other, thus
- y = f(x)
Now 
= - y, hence
The equation for the red graph is
= f(x - 1) → C
Answer:
C. Over the interval [–1, 0.5], the local minimum is 1.
Step-by-step explanation:
From the graph we observe the following:
1) x intercepts are two points.
ii) y intercept = 1
f(x) = y increases from x=-infinity to -1.3
y decreases from x=-1.3 to 0
Again y increases from x=0 to end of graph.
Hence in the interval for x as (-1.3, 1) f(x) has a minimum value of (0,1)
i.e. there is a minimum value of 1 when x =0
Since [-1,0.5] interval contains the minimum value 1 we find that
Option C is right answer.
There is a local minimum of 1 in the interval [-1,0.5]
