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3 years ago

8

How many digits are there in Hindu- Arabic system

1 answer:

kobusy [5.1K]3 years ago

5 0

10 digits.
0, 1, 2, 3, 4, 5, 6, 7, 8, and 9

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Which shows how to find the value of this expression when x=-2 and y=5? (3x^3y^-2)^2

yanalaym [24]

Answer:

1st one

Step-by-step explanation:

I have answered ur question

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3 years ago

Consider the following system of equations:

Umnica [9.8K]

X=3 and the work to get the answer is attached.

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3 years ago

What is the zero of the function

olga_2 [115]

Answer:

$x=6$ (or 6)

Step-by-step explanation:

<u>Set f(x)=0:</u>

$f(x)=\frac{x^2+x-42}{x^2+3x-28}$

$0=\frac{x^2+x-42}{x^2+3x-28}$

$0=x^2+x-42$

$0=(x+7)(x-6)$

$x=-7$ or $x=6$

<u>Now check both solutions:</u>

$f(-7)=\frac{(-7)^2+(-7)-42}{(-7)^2+3(-7)-28}$

$f(-7)=\frac{49-7-42}{49-21-28}$

$f(-7)=\frac{42-42}{28-28}$

$f(-7)=\frac{0}{0}$

Therefore, $x\neq-7$ because there is a hole at $(-7,0)$ . The denominator, in addition, can never be 0, so the function is undefined for $x=-7$ .

$f(6)=\frac{(6)^2+(6)-42}{(6)^2+3(6)-28}$

$f(6)=\frac{36+6-42}{36+18-28}$

$f(6)=\frac{42-42}{54-28}$

$f(6)=\frac{0}{24}$

$f(6)=0$

Since $f(6)=0$ , then $x=6$ is the only zero of the function.

4 0

3 years ago

The value of a car depreciates by 18 per cent per year. Work out the current value of a car brought 4 years ago for £20000.

andrey2020 [161]

18% of 20000 = 3600(0.18 x 20000 = 3600)
3600 x 4 years = 14400
(original value - depreciated value in 4 years: 20000 - 14400 = 5600)
The current value of the car is at £5600

8 0

3 years ago

Find the sum of 7a 3 14a 12 and -6a 3 12a 2 -7.

Mademuasel [1]

Assuming the missing signs are pluses, that would work out to a^3 + 12a^2 + 14a + 5

3 0

3 years ago