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Liula [17]
3 years ago
8

How many digits are there in Hindu- Arabic system

Mathematics
1 answer:
kobusy [5.1K]3 years ago
5 0
10 digits.
0, 1, 2, 3, 4, 5, 6, 7, 8, and 9
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Help me please these are for my finals. ! :(
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Answer:

negitive

Step-by-step explanation:

good luck on finals

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2 years ago
What is 15% of 140
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15% of 40

Of = Multiplication

15% Multiply by 40

Set up a equation

15/100= x/140

Cross Multiply

15* 140= 100*x

2100= 100x

Divide both sides by 100x

2100/100x= 100x/100x

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In Happyville, the ideal family has four children, at least two of which are girls. If you randomly select a Happyville family t
sleet_krkn [62]

Answer:

0.3125 = 31.25% probability that it is not ideal.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either it is a girl, or they are not. The probability of a child being a girl is independent of any other child. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.5 probability of a children being a girl:

This means that p = 0.5

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Not ideal is less than two girls, so this is P(X < 2).

Four children means that n = 4. So

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.5)^{0}.(0.5)^{4} = 0.0625

P(X = 1) = C_{4,1}.(0.5)^{1}.(0.5)^{3} = 0.25

P(X < 2) = P(X = 0) + P(X = 1) = 0.0625 + 0.25 = 0.3125

0.3125 = 31.25% probability that it is not ideal.

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2 years ago
What is the simplified form of the fraction below 15/25
scZoUnD [109]

Answer:

\frac{15}{25} ÷ \frac{5}{5} = \frac{3}{5}

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in a class of 147 students, 95 are taking math, 73 are taking science, and 52 are taking both math and science. if one student i
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