Answer:
She gave a $2.00 tip witch would be %20 of her meal cost.
Step-by-step explanation:
</3 PureBeauty
There are 30 kids in the class and 6 voted for Sunday which means that there is a 6/30 chance that the student picked Sunday or a 20% chance the kid picked Sunday.
The semicircle is 25pi or 78.54
The rectangle is 120 (12*10)
The triangle is 24 (.5*12*4)
So the total is 222.54 (78.54+120+24)
Hello!
The formula for circumference is
![2\pi r](https://tex.z-dn.net/?f=%202%5Cpi%20r)
and the formula for area of a circle is
![\pi r^{2}](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E%7B2%7D%20)
. Armed with these formulas, we can begin to find the circumferences and areas of the circles.
20.
C =
![2 \pi r](https://tex.z-dn.net/?f=2%20%5Cpi%20r%20)
C =
![2 \pi (6.5)](https://tex.z-dn.net/?f=2%20%5Cpi%20%286.5%29)
C =
![13 \pi](https://tex.z-dn.net/?f=13%20%5Cpi%20)
C = 13(3.14)
C = 40.8
A =
![\pi r^{2}](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E%7B2%7D%20)
A =
![\pi (6.5)^{2}](https://tex.z-dn.net/?f=%20%5Cpi%20%286.5%29%5E%7B2%7D%20)
A =
![\pi (42.25)](https://tex.z-dn.net/?f=%20%5Cpi%20%2842.25%29)
A = 132.7
The circumference of the circle is 40.8 in and the area of the circle is 132.7 in².21.
[Since we are given the diameter for this problem, to find the circumference, we no longer need to multiply the radius by 2 as in
![2 \pi r](https://tex.z-dn.net/?f=2%20%5Cpi%20r)
because the diameter is the radius × 2. For
![\pi r^{2}](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E%7B2%7D%20)
we do need to divide the diameter by 2.]
C =
![15.7 \pi](https://tex.z-dn.net/?f=15.7%20%5Cpi%20)
C = 49.3
A =
![\pi r^{2}](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E%7B2%7D%20)
A =
![\pi (7.85)^{2}](https://tex.z-dn.net/?f=%20%5Cpi%20%287.85%29%5E%7B2%7D%20)
A =
![61.62 \pi](https://tex.z-dn.net/?f=61.62%20%5Cpi%20)
A = 193.5
The circumference of the circle is 49.3 in and the area of the circle is 193.5 in².
And that is all there is to it. I hope this helps you! (:
Answer:
That is a rectangular prism
Step-by-step explanation:
Because I'm smart