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2 years ago

8

Write an equation of a line that passes through (1,1)and (6,6)

1 answer:

Ghella [55]2 years ago

7 0

Answer:

y=x

Step-by-step explanation:

When y=x, then the line goes up 1 and right 1.

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Which are true and which are false?

patriot [66]

Answer:

true

Step-by-step explanation:

3 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

HELP ASAP WILL GIVE BRAINLIST

Basile [38]

The answer to your question is 0

6 0

3 years ago

Read 2 more answers

The area of a rectangular garden is 18z+24 square feet. What are the possible dimensions of the garden?

Lelechka [254]

Given:

The area of the rectangular garden is 18z+24 sq ft.

To find the possible dimensions of the garden.

Formula

The area of the rectangular garden is

$A = lb$

where,

l be the length of the rectangle

b be the width.

Let us take l and b be the length and width of the given rectangular park respectively.

Now,

According to the problem,

$lb = 18z+24$

or, $lb = 6(3z+4)$

We can determine that,

l = 6 and b = 3z+4 or vice versa.

Hence,

The possible length and width of the rectangular garden is 6 and (3z+4) respectively.

7 0

3 years ago

Pre calculus help!! pH of substance which has a hydronium ion concentration? help please!!

disa [49]

-log(5.4x10^-9) = 8.27 = 8.3

since 8.3 is greater than 7 it is basic

so the last answer is correct

7 0

3 years ago