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3 years ago

Write an equation of a line that passes through (1,1)and (6,6)

Mathematics

1 answer:

Ghella [55]3 years ago

7 0

Answer:

y=x

Step-by-step explanation:

When y=x, then the line goes up 1 and right 1.

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in an examination ,80%examines passed in English ,70%in mathematics and 60% in both subject if 45 examines failed in both find t

stiv31 [10]

Answer:

135 and 135

Step-by-step explanation:

The computation is shown below:

The number of examiners who passed in only one subject is as follows

= n(E) - n(E ∩M) + n(M) - n(E ∩M)

= (80 - 60 + 70 - 60)%

= 30%

Now the number of students who passed in minimum one subject is

n(E∪M) = n(E) + n(M) - n(E ∩M)

= 80 - + 70 - 60

= 90%

Now the number of students who failed in both subjects is

= 100 - 90%

= 10% of total students

= 45

So total number of students appeared for this 450

So, those who passed only one subject is

= 450 × 30%

= 135

Now the Number of students who failed in mathematics is

= 100% - Passed in Mathematics

= 100% - 70%

= 30% of 450

= 135

4 0

3 years ago

Only do the last two word problems. thanks!

bazaltina [42]

Answer:

x=24-1

x=9+1

Step-by-step explanation:

3 0

3 years ago

Write cubed root of x2 using a fractional exponent

SIZIF [17.4K]

$\sqrt[3]{x^2} = x^{ \frac{2}{3} }$

6 0

3 years ago

Pyramid A is a square pyramid with a base side length of 14 inches and a height of 6 inches. Pyramid B has a volume of 3,136 cub

leonid [27]

The Volume of PYRAMID A is 8 times greater than the Volume of PYRAMID B as obtained by taking the ratio of the volume of both pyramids.

Volume of a square based pyramid is given as :

$V = a^2h/3$

Where; h = height ; a = base edge

Hence, Volume of PYRAMID A :

$V = 14^2 * (6/3)\\\\V = 392 in^3$

Volume of PYRAMID B = 3,136 in³

Divide Volume of pyramid B by pyramid A :

$3136 in^3 / 392 in^3$

= 8 times

Expressing as a percentage, multiply by 100% ;

8 * 100% = 800%

Therefore, The volume of PYRAMID B is 800% times GREATER THAN that of PYRAMID A.

Learn more :

brainly.com/question/17615619

8 0

3 years ago

Read 2 more answers

An airline finds that 5% of the persons making reservations on a certain flight will not show up for the flight. If the airline

vivado [14]

Answer:

The answer to the question is;

The probability that a seat will be available for every person holding a reservation and planning to fly is 0.63307.

Step-by-step explanation:

Let the sample size =n = 100

The success probability = 5 % = 0.05

Number of tickets sold = 105 tickets

In the case where there the airline has found that 5 % will not show up, then every passenger should have a seat, we have

A Binomial distribution is appropriate where there is a chance for a certain number of successful outcomes from a number of independent trails

However n·p and n·q must be ≥ 5 for there to be a normal approximation of a Binomial distribution thus

n·p = 105×0.05 = 5.25 ≥ 5

and n·q = n(1 - p) = 105 (1 - 0.05) = 99.75 ≥ 5

As the requirements are met, we can proceed with the approximation of the Binomial distribution by the normal distribution

$z = \frac{x-np}{\sqrt{np(1-p)} } = \frac{4.5 - 105*0.05}{\sqrt{105*0.05(1-0.05)} }$ = - 0.3358

We therefore have P(x ≥ 5) = P( x > 4.5) = P(z > -0.34) = 1 - P(z < -0.34) = 1 -0.36693 = 0.63307

Another way to solve the question is as follows

p = 0.95 q = 0.05

μ = np = 0.95*105 = 99.75, σ = $\sqrt{npq}$ = 2.233

P (x≤100) = P $(z$ = P(z<0.34) = 0.63307.

6 0

3 years ago