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lawyer [7]
2 years ago
8

Write an equation of a line that passes through (1,1)and (6,6)

Mathematics
1 answer:
Ghella [55]2 years ago
7 0

Answer:

y=x

Step-by-step explanation:

When y=x, then the line goes up 1 and right 1.

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Which are true and which are false?
patriot [66]

Answer:

true

Step-by-step explanation:

3 0
3 years ago
Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations
marusya05 [52]

Answer:

Sin \angle A =0.80

Cos \angle A=0.60

Sin \angle B =0.60

Cos \angle B=0.80

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

Sin \theta =\frac{Opposite}{Hypotenuse} and

Cos \theta =\frac{Adjacent}{Hypotenuse}

So:

Sin \angle A =\frac{BC}{BA}

Substitute values for BC and BA

Sin \angle A =\frac{8cm}{10cm}

Sin \angle A =\frac{8}{10}

Sin \angle A =0.80

Cos \angle A=\frac{AC}{BA}

Substitute values for AC and BA

Cos \angle A=\frac{6cm}{10cm}

Cos \angle A=\frac{6}{10}

Cos \angle A=0.60

Solving (b): Sine and Cosine B

In trigonometry:

Sin \theta =\frac{Opposite}{Hypotenuse} and

Cos \theta =\frac{Adjacent}{Hypotenuse}

So:

Sin \angle B =\frac{AC}{BA}

Substitute values for AC and BA

Sin \angle B =\frac{6cm}{10cm}

Sin \angle B =\frac{6}{10}

Sin \angle B =0.60

Cos \angle B=\frac{BC}{BA}

Substitute values for BC and BA

Cos \angle B=\frac{8cm}{10cm}

Cos \angle B=\frac{8}{10}

Cos \angle B=0.80

Using a calculator:

A = 53^{\circ}

So:

Sin(53^{\circ}) =0.7986

Sin(53^{\circ}) =0.80 -- approximated

Cos(53^{\circ}) = 0.6018

Cos(53^{\circ}) = 0.60 -- approximated

B = 37^{\circ}

So:

Sin(37^{\circ}) = 0.6018

Sin(37^{\circ}) = 0.60 --- approximated

Cos(37^{\circ}) = 0.7986

Cos(37^{\circ}) = 0.80 --- approximated

8 0
3 years ago
Read 2 more answers
HELP ASAP WILL GIVE BRAINLIST
Basile [38]

The answer to your question is 0                                                                                                                



6 0
3 years ago
Read 2 more answers
The area of a rectangular garden is 18z+24 square feet. What are the possible dimensions of the garden?
Lelechka [254]

Given:

The area of the rectangular garden is 18z+24 sq ft.

To find the possible dimensions of the garden.

Formula

The area of the rectangular garden is

A = lb

where,

l be the length of the rectangle

b be the width.

Let us take l and b be the length and width of the given rectangular park respectively.

Now,

According to the problem,

lb = 18z+24

or, lb = 6(3z+4)

We can determine that,

l = 6 and b = 3z+4 or vice versa.

Hence,

The possible length and width of the rectangular garden is 6 and (3z+4) respectively.

7 0
3 years ago
Pre calculus help!! pH of substance which has a hydronium ion concentration? help please!!
disa [49]

-log(5.4x10^-9) = 8.27 = 8.3

 since 8.3 is greater than 7 it is basic

so the last answer is correct

7 0
3 years ago
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