Question

The robot HooRU is lost in space, floating around aimlessly, and radiates heat into the depths of the cosmos at the rate of 13.5 W. HooRU's surface area is 1.51 m^2 and the emissivity of its surface is 0.209. Ignore the radiation HooRU absorbs from the cold universe. What is HooRU's temperature?

Answer 1

Answer:

165.73 K

Explanation:

The computation of HooRU's temperature is shown below:-

As per the stefan's law, the power radiated by black body radiations which is

$P = eA\sigma T^4$

where  

A indicates surface area

e indicates emissitivity

T indicates temperature

now, we will put the values in the above equation

$13.5 = 0.209 \times 1.51 \times \sigma \times T^4$

After solving the above equation we will get temperature which results

= 165.73 K

Therefore for computing the HooRU's temperature we simply applied the above formula.