Answer: x = 5, y = 2/5
Step-by-step explanation:
We have the system of equations:
6*x + 5*y = 32
2*x + 5*y = 12
To solve it, we can start by isolating one of the variables in one of the equations.
Because in both of them we have the term 5*y, i will isolate 5*y in the second equation:
5*y = 12 - 2*x
Now let's replace it in the first equation:
6*x + (12 - 2*x) = 32
Now let's solve it for x
6*x + 12 - 2*x = 32
(6*x - 2*x) = 32 - 12 = 20
4*x = 20
x = 20/4 = 5
Now we know the value of x, we can replace it in the equation:
5*y = 12 - 2*x
to find the value of y.
5*y = 12 - 2*5
5*y = 2
y = 2/5
Then the solution of the system is x = 5, y = 2/5
Answer:
x=2
Step-by-step explanation:
Step 1: Add 2x to both sides.
4x−3+2x=−2x+9+2x
6x−3=9
Step 2: Add 3 to both sides.
6x−3+3=9+3
6x=12
Step 3: Divide both sides by 6.
<u>6</u><u>x</u><u> </u><u>=</u><u> </u><u>1</u><u>2</u>
6 6
x=2
Answer:
b=−1/14ot+2
Step-by-step explanation:
Let's solve for b.
to−8+5b=−6+26−9b
Step 1: Add 9b to both sides.
ot+5b−8+9b=−9b+20+9b
ot+14b−8=20
Step 2: Add -ot to both sides.
ot+14b−8+−ot=20+−ot
14b−8=−ot+20
Step 3: Add 8 to both sides.
14b−8+8=−ot+20+8
14b=−ot+28
Step 4: Divide both sides by 14.
14b
14
=
−ot+28
14
b=
−1
14
ot+2
The square root of 73. Since the theorem is a^2+b^2=c^2 and only works with right triangles. You take 2/2 the base so you have a right triangles with a hypotenuse if 9 and a side of 3. Then you just plug in to solve.
13+3k=11
-Move constant to the right-hand side and change its sign
3k=11-13
Calculate the difference
3k=-2
Divide both sides by 3
K= -2/3
