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pishuonlain [190]
3 years ago
12

PLEASEEE HURRYYYY how many triangles can be constructed with sides measuring 6cm 2cm 7cm

Mathematics
1 answer:
Luden [163]3 years ago
3 0
C. None. I’m pretty sure
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He short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown number of inches
goldenfox [79]
The sum of two adjacent sides is 11 inches, so the long sides are 9 inches. The "unknown number" must be 12.
7 0
3 years ago
Work out the value of each expression, when r= 2.5 and t = 6.
Usimov [2.4K]

Answer:

a)  4(t - r) = 4(6 - 2.5) = 4 x 3.5 = 14

b)  4t - r = (4 x 6) - 2.5 = 24 - 2.5 = 21.5

c)  2(3t - 10) = 2(3 x 6 - 10) = 2(18 - 10) = 2 x 8 = 16

d)  (t - 2)² = (6 - 2)² = 4² = 4 x 4 = 16

e) cannot decipher the equation

f)  6r + t = 6 x 2.5 + 6 = 15 + 6 = 21

8 0
2 years ago
Read 2 more answers
Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w
siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.

$r(t)=x(t)i+y(t)j$  is a parametrization of the most $\text{rapid increase curve}$ , then

$\frac{dx}{dt}=\frac{dx}{dt}i+\frac{dy}{dt}j$ is a tangent to the curve.

So then we have that $\frac{dr}{dt}=\lambda \triangledown C$

$\Rightarrow \frac{dx}{dt}=-\frac{2\lambda x}{10^4}e^{-(x^2+2y^2)/10^4}, \frac{dy}{dt}=-\frac{4\lambda y}{10^4}e^{-(x^2+2y^2)/10^4} $

∴ $\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{2y}{x}$

Using separation of variables,

$\frac{dy}{y}=2\frac{dx}{x}$

$\int\frac{dy}{y}=2\int \frac{dx}{x}$

$\ln y=2 \ln x$

⇒ y = kx^2 for some constant k

but we know that $y(x_0)=y_0$

$\Rightarrow kx_0^2=y_0$

$\Rightarrow k =\frac{y_0}{x_0^2}$

∴ The path of the shark will follow is along the parabola

$y=\frac{y_0}{x_0^2}x^2$

$y=y_0\left(\frac{x}{x_0}\right)^2$

7 0
2 years ago
Please help I really do not understand this yeah I can be weird sometimes but please help will mark the correct answers brainies
NISA [10]

Answer:

Step-by-step explanation:

1.0.39

2.0.33

3.Loose

4.0.14

I did the first four... hope that helps

3 0
2 years ago
The tap drips 25 drops in I min​
Alex_Xolod [135]

Answer:

60 divided 25

Step-by-step explanation:

8 0
2 years ago
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