This can be displayed as a system of equations.
x = 3 + 5y
x - y = 11
Because we have a value of x we can plug it into the value of x in the second equation.
(3 + 5y) - y = 11
3 + 5y - y = 11
Combine like terms.
3 + 4y = 11
Subtract 3 from both sides.
4y = 8
Divide both sides by 4.
y = 2
Now that we have a constant value for y, we can replace the value of y in the second equation with 2 to solve for x.
x - 2 = 11
Add 2 to both sides.
x = 13
Now, let's verify.
13 = 3 + 5(2)
13 = 3 + 10
13 = 13 √ this is correct.
13 - 2 = 11
11 = 11 √ this is correct.
The first number, or x, is equal to 13.
The second number, or y, is equal to 2.
Real numbers that you cannot represent as a quotient of two integers are irrational numbers.
The diagram is not given. I will however write out each polynomial, so that you can select whichever corresponds to your question.
Step-by-step explanation:
(2x + 8)(4x + 8)
= 8x² + 16x + 24x + 64
= 8x² + 40x + 64
= 8(x² + 5x + 8)
(x + 2)(x+4)
= x² + 4x + 2x + 8
= x² + 6x + 8
(x + 1)(x+8)
= x² + 8x + x + 8
= x² + 9x + 8
* (*+ 4x)(2x + 3) NOT CLEAR
The answer would be positive 24. The reason being is because of the fact that two negatives when multiplied cancel the negative. Also 12 * 2 is 24 so yeah