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Ann [662]
3 years ago
10

Jacob’s daily tips this work week were $99, $78, $58, $91, $90, and $68. Is Jacob correct in thinking that the mean best represe

nts how much money he makes in daily tips?
Mathematics
2 answers:
valina [46]3 years ago
8 0
The mean means that its the average of the numbers. So Jacob is wrong if he adds up all the tips. Because for the mean you add all the numbers then divide by how many numbers there are
alexandr1967 [171]3 years ago
3 0
Jacob is correct in thinking that because the mean represents the average of several quantities
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Ms. Wood took m1/6 of an hour to review each question fromt the Science test. How many questions can she review in 2/3 of an hou
Archy [21]

Answer: 4 questions

Step-by-step explanation:

16h=10 min

2/3=40 min

Use equation:

1:10=x:40

40=10x

x=40/10

x=4

5 0
3 years ago
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
N^2- 5n +4=0 quadratic equation
luda_lava [24]

Answer:

n = 1, 4

Step-by-step explanation:

Step 1: Write equation

n² - 5n + 4 = 0

Step 2: Solve for <em>n</em>

<u>Factor:</u> (n - 4)(n - 1) = 0

<u>Find roots:</u> n = 1, 4

Step 3: Check

<em>Plug in n to verify if it's a solution.</em>

1² - 5(1) + 4 = 0

1 - 5 + 4 = 0

-4 + 4 = 0

0 = 0

4² - 5(4) + 4 = 0

16 - 20 + 4 = 0

-4 + 4 = 0

0 = 0

7 0
3 years ago
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SIZIF [17.4K]

Answer:

27.275

Step-by-step explanation:

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3 years ago
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What is the square root of 361
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The answer would be 19. If u have a calculator you can just plug it in though
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