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3 years ago

What was Galileo’s contribution to the study of motion?

Physics

1 answer:

pshichka [43]3 years ago

5 0

Hello! :)

A study of motion is basically like physics.

Hence, using the telescope, Galileo discovered the mountains on the moon, the spots on the sun, and four moons of Jupiter. His discoveries provided the evidence to support the theory that the earth and other planets revolved around the sun.

Hope this helped and I hope I answered in time!

Good luck!

~ Destiny ^_^

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In the formula Q = m × c ×Δ T, which symbol represents specific heat? c m Q Δ T

Licemer1 [7]

Answer:

C is your answer.

Explanation:

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3 years ago

During most of its lifetime, s star maintains an equilibrium size in which the inward force of gravity on each atom is balanced

frez [133]

Answer:

$r_f=137493m$

$v=8638940m/s$

Explanation:

During this process the mass $M=2\times10^{30}Kg$ will be considered constant. We start from a radius $r_i=7\times10^8m$ and a period $T_i=30\ days=(30)(24)(60)(60)s=2592000s$ . The final period is $T_f=0.1s$ .

Angular momentum <em>L</em> is conserved in this process. We can use the formula $L=I\omega$ , where I is the momentum of inertia (which for a solid sphere is $I=\frac{2mr^2}{5}$ ) and $\omega=\frac{2\pi }{T}$ is the angular velocity, so we can write the star's angular momentum as:

$L=I\omega=\frac{2mr^2}{5}\frac{2\pi }{T}=\frac{4\pi mr^2 }{5T}$

Since $L_f=L_i$ we have:

$\frac{4\pi mr_f^2 }{5T_f}=\frac{4\pi mr_i^2 }{5T_i}$

Which can be simplified as:

$\frac{r_f^2 }{T_f}=\frac{r_i^2 }{T_i}$

Which means:

$r_f=\sqrt{\frac{r_i^2 T_f}{T_i}}=r_i \sqrt{\frac{T_f}{T_i}}$

Which for our values is:

$r_f=r_i \sqrt{\frac{T_f}{T_i}}=(7\times10^8m) \sqrt{\frac{0.1s}{2592000s}}=137493m$

And we calculate the speed of a point on the equator by dividing the final circumference over the final period:

$v=\frac{C_f}{T_f}=\frac{2\pi r_f}{T_f}=\frac{2\pi (137493m)}{(0.1s)}=8638940m/s$

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4 years ago

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bagirrra123 [75]

Reduce friction because friction just makes things harder

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3 years ago

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A 1650 kg car accelerates at a rate of 4.0 m/s. How much force is the car's engine producing?

lakkis [162]

The car produces 412.5 KG per m/s

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3 years ago

According to the three laws of planetary motion, planetary orbits are in the shape of a/an

Talja [164]

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4 years ago