56.321, 56.32, 56.2 is the answer
Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:

where r = radius of orbit of Hubble Space Telescope
G = gravitational constant = 
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r = 
M = 
Therefore, T will be:


The orbital period of the Hubble Space Telescope is 5069.04 seconds.
Here is your answer:
First find the notations:
5.0×10^2=500.
1.0×10^3=1,000
Then you multiply:
1,000×500=500,000
Your answer is...
=500,000 or 5.0×10^4
Answer:

Explanation:
#Using the conservation of momentum , momentum before equals momentum after(
.
-Initial speed is 5.2m/s while the cart is at rest. After, the velocity will be of a combined(bag+cart) mass.
Hence:

Hence, the final velocity of the cart and bag is 1.77m/s