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hoa [83]
3 years ago
13

A sled starts at rest with 51,450 J of potential energy. After traveling part of the way down the slope, the sled has 32,781 J o

f potential energy. If there is no friction, what is the kinetic energy of the sled?
Physics
1 answer:
Ugo [173]3 years ago
8 0
Because of conservation of energy, ep is equal to ek.
at that point ep=ek
the kinetic energy would be 32,781J

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How high a hill can a car coast up (engine disengaged) if work done by friction is negligible and
aev [14]

Answer:

h= 46.66 m

Explanation:

Given that

Initial speed of the car ,u = 110 km/h

We know that

1 km/h= 0.277 m/s

u= 30.55 m/s

lets height gain by car is h.

The final speed of the car will be zero at height h.

v²=u²- 2 g h

v= 0 m/s

0²=30.55²- 2 x 10 x h           ( g = 10 m/s²)

h= 46.66 m

4 0
3 years ago
Uranium-238 eventually decays into
GalinKa [24]
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4 0
3 years ago
How many planets are in our Solar system?<br> I'll give brainliest
Dima020 [189]

Answer:

The following is Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune

That is from our solar system

Explanation:

8 0
2 years ago
At the nose of a missile in flight, the pressure and temperature are 5.6 atm and 850°R, respectively. Calculate the density and
Contact [7]

To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to

1atm = 2116lb/ft^2

The ideal gas equation said us that,

PV = nRT

Here,

P = pressure

V = Volume

R = Gas ideal constant

T = Temperature

n = Amount of substance (at this case the mass)

Then

\frac{n}{V} = \frac{P}{RT}

The amount of substance per volume is the density, then

\rho = \frac{P}{RT}

Replacing with our values,

\rho = \frac{5.6*2116}{1716*850}

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Finally the specific volume would be

v = \frac{1}{\rho}

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6 0
3 years ago
20. In a parallel RL circuit, 10 mA flows through the resistor and 4 mA flows through the inductor. What phase angle separates v
stellarik [79]

Answer:

Option D: 21.8 degrees

Explanation:

In a parallel RL circuit, the current in the resistor R and that in the inductor L are separated among themselves 90 degrees as illustrated in the attached image. In the image the current in the resistor is represented in orange, that of the inductor in blue, and the total current (vector addition of the previous two) is represented  in red, forming a certain angle (theta) with respect to the current in the resistor. The output voltage is the same as the input voltage as measured over the resistor R.

Therefore, the phase angle that separated output voltage and total current can be obtained using the fact that tan(phase angle) = \frac{I_l}{I_R} = \frac{x}{y} \frac{4}{10}, therefore the angle is the arctangent of 4/10:

arctang(\frac{4}{10} )= 21.801 degrees.

8 0
3 years ago
Read 2 more answers
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