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2 years ago

I will give you Brainiest if you are right.

Mathematics

2 answers:

Lilit [14]2 years ago

7 0

Answer:

F. Six times a number less nine

This is the only one that doesn't make sense

Sorry if im wrong

Bess [88]2 years ago

6 0

Answer:

I think its 'H'

Step-by-step explanation:

Sorry if i'm wrong i tried my best

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Over the interval [0,2pi), what are the solutions to cos(2x) = cos(x)? check all that apply

kykrilka [37]

$\cos(2x) = \cos(x)$

Solution (1)

$2x = x + 2k\pi$

$2x - x = 2k\pi$

$x = 2k\pi$

for k=0 / for k=1 / for k=-1

x=0 / x=2π / x=-2π

acc / acc / rej

solution (2)

$2x = - x + 2k\pi$

$2x + x = 2k\pi$

$3x = 2k\pi$

$x = \frac{2k\pi}{3}$

for k=0 / for k=1 / for k=-1

x=0 / x=2π/3 / x=-2π/3

acc / acc / rej

Note that i'm trying values of K which make the answer belong to our interval;

So our solution which i will represent as a set is;

S € {0,2π/3,2π}

6 0

2 years ago

1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x

qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is $(2x+10)^\circ$ , so the measure of arc DF is

$m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ$

The inscribed angle theorem tells us that the central angle subtended by arc DF, $\angle DOF$ , has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

$m\angle DOF=2m\angle OEF=64^\circ$

so the measure of arc DF is also 64 degrees. So we have

$170-2x=64\implies106=2x\implies\boxed{x=53}$

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

$m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ$

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

$m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}$